In: Statistics and Probability
I measured the height of a sample of marigolds by the Union. The values were 7, 10, 12, 9, 10, 12, 10, 9, 10, 11, 8, 12, 10, 9, 11, 10, 9, 10, and 11 inches. I then walked downtown and saw some marigolds growing on Broadway, so I measured a sample of them. The values were 6, 9, 13, 10, 12, 10, 8, 11, 7, 14, 10, 12, 8, 7, 14, 9, 8, 13. Calculate the mean, the variance, and the standard deviation for the Union and Broadway samples. If I wanted to select artificially for different sized marigolds, from which group of plants would I take seeds? Explain.
UNION
The sample size is n=19. The provided sample data along with the
data required to compute the sample mean
and sample variance
are shown in the table below:
Union | Union2 | |
7 | 49 | |
10 | 100 | |
12 | 144 | |
9 | 81 | |
10 | 100 | |
12 | 144 | |
10 | 100 | |
9 | 81 | |
10 | 100 | |
11 | 121 | |
8 | 64 | |
12 | 144 | |
10 | 100 | |
9 | 81 | |
11 | 121 | |
10 | 100 | |
9 | 81 | |
10 | 100 | |
11 | 121 | |
Sum = | 190 | 1932 |
The sample mean
is computed as follows:
Also, the sample variance
is
Therefore, the sample standard deviation s is
BROADWAY
The sample size is n=18. The provided sample data along with the
data required to compute the sample mean
and sample variance
are shown in the table below:
Broadway | Broadway2 | |
6 | 36 | |
9 | 81 | |
13 | 169 | |
10 | 100 | |
12 | 144 | |
10 | 100 | |
8 | 64 | |
11 | 121 | |
7 | 49 | |
14 | 196 | |
10 | 100 | |
12 | 144 | |
8 | 64 | |
7 | 49 | |
14 | 196 | |
9 | 81 | |
8 | 64 | |
13 | 169 | |
Sum = | 181 | 1927 |
The sample mean
is computed as follows:
Also, the sample variance
is
Therefore, the sample standard deviation s is
If we wanted to select artificially for different sized marigolds, we should take the seed from the Broadway plants. This is because they have more variability in their heights as compared to union plants, so we will have a mix of different sized marigolds.
Let me know in the comments if anything is not clear. I will reply ASAP! Please do upvote if satisfied!