In: Statistics and Probability
2. Nine experts rated two brands of Colombian coffee in a taste-testing experiment. A rating on a 7-point scale (1=extremely unpleasing, 7 = extremely pleasing) is given for each of four characteristics: taste, aroma, richness, and acidity. The following data contain the ratings accumulated over all four characteristics:
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BRAND |
||
EXPERT |
A |
B |
C.C. |
24 |
26 |
S.E. |
27 |
27 |
E.G. |
19 |
22 |
B.I. |
24 |
27 |
C.M. |
22 |
25 |
C.N. |
26 |
27 |
G.N. |
27 |
26 |
R.M |
25 |
27 |
P.V. |
22 |
23 |
a) At the 0.05 level of significance, is there evidence of a difference in the mean ratings between the two brands?
b) What assumption is necessary about the population distribution in order to perform this test?
c) Construct and interpret a 95% confidence interval estimate of the difference in the mean ratings between the two brands.
using minitab>stat>basic stat>two sample t
we have
Two-Sample T-Test and CI: A, B
Two-sample T for A vs B
N Mean StDev SE Mean
A 9 24.00 2.65 0.88
B 9 25.56 1.88 0.63
Difference = μ (A) - μ (B)
Estimate for difference: -1.56
95% CI for difference: (-3.85, 0.74)
T-Test of difference = 0 (vs ≠): T-Value = -1.44 P-Value = 0.170 DF
= 16
Both use Pooled StDev = 2.2943
a ) At the 0.05 level of significance,since p value of t = 0.170>0.05 so we cannot conclude that there is a difference in the mean ratings between the two brands.
Ans b ) the assumptions are, samples should be independent
population from which samples are drawn should be normal.
and samples drom the bopulation should be drawn randomly
Ans c ) 95% confidence interval is (-3.85, 0.74) .we are 95% confident that the difference in the mean ratings between the two brands lies in between (-3.85, 0.74)