In: Statistics and Probability
To investigate the fluid mechanics of swimming, twenty swimmers each swam a specified distance in a water-filled pool and in a pool where the water was thickened with food grade guar gum to create a syrup-like consistency. Velocity, in meters per second, was recorded and the results are given in the table below.
| Swimmer | Velocity (m/s) | |
|---|---|---|
| Water | Guar Syrup | |
| 1 | 0.90 | 0.93 |
| 2 | 0.92 | 0.97 |
| 3 | 1.00 | 0.95 |
| 4 | 1.10 | 1.14 |
| 5 | 1.20 | 1.23 |
| 6 | 1.25 | 1.23 |
| 7 | 1.25 | 1.27 |
| 8 | 1.30 | 1.30 |
| 9 | 1.35 | 1.34 |
| 10 | 1.40 | 1.42 |
| 11 | 1.40 | 1.44 |
| 12 | 1.50 | 1.53 |
| 13 | 1.65 | 1.58 |
| 14 | 1.70 | 1.70 |
| 15 | 1.75 | 1.80 |
| 16 | 1.80 | 1.77 |
| 17 | 1.80 | 1.84 |
| 18 | 1.85 | 1.86 |
| 19 | 1.90 | 1.88 |
| 20 | 1.95 | 1.95 |
(A) Find the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.)
t=
P-value=
Sol:
Ho:mu1=mu2
Ha:mu not =mu2
In excel go to data >Data analysis>t test assuming unequal variance
we get

from
| t-Test: Two-Sample Assuming Unequal Variances | |||
| Water | Guar Syrup | ||
| Mean | 1.4485 | 1.4565 | |
| Variance | 0.112677 | 0.109298 | |
| Observations | 20 | 20 | |
| Hypothesized Mean Difference | 0 | ||
| df | 38 | ||
| t Stat | -0.07594 | ||
| P(T<=t) one-tail | 0.469934 | ||
| t Critical one-tail | 1.685954 | ||
| P(T<=t) two-tail | 0.939868 | ||
| t Critical two-tail | 2.024394 |
t=--0.1
p value=0.940