In: Statistics and Probability
Assume that random guesses are made for six multiple choice questions on an SAT test, so that there are n equals 6 trials, each with probability of success (correct) given by p equals 0.6. Find the indicated probability for the number of correct answers. Find the probability that the number x of correct answers is fewer than 4. Upper P left parenthesis Upper X less than 4 right parenthesis equals nothing (Round to four decimal places as needed.)
Let , X be the number of correct answers.
Here ,
The pmf of X is ,
; x=0,1,2,.....,n and q=1-p
= 0 ; otherwise
Therefore, the indicated probability distribution table is ,
X | P(X=x) | |||
0 | 1 | 1 | 0.004096 | 0.0041 |
1 | 6 | 0.6 | 0.01024 | 0.0369 |
2 | 15 | 0.36 | 0.0256 | 0.1382 |
3 | 20 | 0.216 | 0.064 | 0.2765 |
4 | 15 | 0.1296 | 0.16 | 0.311 |
5 | 6 | 0.07776 | 0.4 | 0.1866 |
6 | 1 | 0.046656 | 1 | 0.0467 |
Now ,
P(X<4)=P(X=4)+P(X=3)+P(X=2)+P(X=1)+P(X=0)
=0.3110+0.2765+0.1382+0.0369+0.0041
=0.7667
Therefore , the probability that the number x of correct answers is fewer than 4 is 0.7667.