Question

In: Statistics and Probability

a. Find the​ mean, median, and range for each of the two data sets. Find the​ mean, median, and range for faculty parking.

Faculty: 3, 4, 2, 1, 2, 3, 5, 4, 4, 3, 2

  

        

Student: 9, 10, 12, 6, 11, 14, 5, 8, 10, 14, 13

   

     

   

    

The following data sets give the ages in years of a sample of cars in a faculty parking lot and a student parking lot at a college. Complete parts​ (a) through​ (e).

.

a. Find the​ mean, median, and range for each of the two data sets. Find the​ mean, median, and range for faculty parking.

meanequals=3

median equals=3

range equals=4

​(Round to the nearest hundredth as​ needed.)

Find the​ mean, median, and range for student parking.

meanequals=10.18

median equals=10

range equals=9

​(Round to the nearest hundredth as​ needed.)

b. Give the​ five-number summary and draw a boxplot for each of the two data sets. Give the​ five-number summary for faculty parking.

low equals=

lower =

quartile equals =

median equals =

upper =

quartile equals =

high equals =

       

                                           .

Solutions

Expert Solution

part b)

i) For Faculty

3,4,2,1,2,3,5,4,4,3,2

First arrange in ascending order

we get

1,2,2,2,3, 3   ,3,4,4,4,5

So, low value =first number =1

median =middle number of this data which is 3

lower quartile = middle number of data on the left side of median

so we find middle of 1,2,2,2,3

and its 2

so lower quartile =2

upper quartile =middle number of data on the right side of median

so we find middle of 3,4,4,4,5

and its middle is 4

so upper quartile =4

high value is the last number of data in ascending order,

so high value =5

ii) For student

9, 10, 12, 6, 11, 14, 5, 8, 10, 14, 13

First arrange in ascending order

we get

5,6,8,9,10,   10   ,11,12,13,14,14

So, low value =first number =5

median =middle number of this data which is 10

lower quartile = middle number of data on the left side of median

so we find middle of 5,6,8,9,10

and its 8

so lower quartile =8

upper quartile =middle number of data on the right side of median

so we find middle of 11,12,13,14,14

and its middle is 13

so upper quartile =13

high value is the last number of data in ascending order,

so high value =14


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