In: Statistics and Probability
Faculty: 3, 4, 2, 1, 2, 3, 5, 4, 4, 3, 2 |
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Student: 9, 10, 12, 6, 11, 14, 5, 8, 10, 14, 13
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The following data sets give the ages in years of a sample of cars in a faculty parking lot and a student parking lot at a college. Complete parts (a) through (e).
.
a. Find the mean, median, and range for each of the two data sets. Find the mean, median, and range for faculty parking.
meanequals=3
median equals=3
range equals=4
(Round to the nearest hundredth as needed.)
Find the mean, median, and range for student parking.
meanequals=10.18
median equals=10
range equals=9
(Round to the nearest hundredth as needed.)
b. Give the five-number summary and draw a boxplot for each of the two data sets. Give the five-number summary for faculty parking.
low equals=
lower =
quartile equals =
median equals =
upper =
quartile equals =
high equals =
.
part b)
i) For Faculty
3,4,2,1,2,3,5,4,4,3,2
First arrange in ascending order
we get
1,2,2,2,3, 3 ,3,4,4,4,5
So, low value =first number =1
median =middle number of this data which is 3
lower quartile = middle number of data on the left side of median
so we find middle of 1,2,2,2,3
and its 2
so lower quartile =2
upper quartile =middle number of data on the right side of median
so we find middle of 3,4,4,4,5
and its middle is 4
so upper quartile =4
high value is the last number of data in ascending order,
so high value =5
ii) For student
9, 10, 12, 6, 11, 14, 5, 8, 10, 14, 13
First arrange in ascending order
we get
5,6,8,9,10, 10 ,11,12,13,14,14
So, low value =first number =5
median =middle number of this data which is 10
lower quartile = middle number of data on the left side of median
so we find middle of 5,6,8,9,10
and its 8
so lower quartile =8
upper quartile =middle number of data on the right side of median
so we find middle of 11,12,13,14,14
and its middle is 13
so upper quartile =13
high value is the last number of data in ascending order,
so high value =14