You need to prepare an acetate buffer of pH 5.52 from a 0.881 M acetic acid...

You need to prepare an acetate buffer of pH 5.52 from a 0.881 M acetic acid solution and a 2.64 M KOH solution. If you have 875 mL of the acetic acid solution, how many milliliters of the KOH solution do you need to add to make a buffer of pH 5.52? The pKa of acetic acid is 4.76.

Expert Solution

pH of acidic buffer = pka + log(ch3cooK/CH33COOH)

pH = 4.9

pka of CH3COOH = 4.76

no of mol of CH3COOH = M*V

= 0.881*0.875

= 0.771 mol

No of mol of CH3COOK = KOH = x mol

5.52 = 4.76+log(x/(0.771-x))

x = 0.657

No of mol of CH3COOK = KOH = 0.657 mol

volume of KOH required = n/M

= 0.657/2.64

= 0.25 l

= 250 ml

queen_honey_blossom answered 1 year ago

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