In: Statistics and Probability
A coffee machine dispenses normally distributed amounts of coffee with a mean of 12 ounces and a standard deviation of 0.2 ounce. If a sample of 9 cups is selected, find the probability that the mean of the sample will be greater than 12.1 ounces. Find the probability if the sample is just 1 cup.
Solution :
Given that,
mean = = 12
standard deviation = = 0.2
n=9
= =12
= / n = 0.2/ 9 = 0.067
P( > 12.1) = 1 - P( < 12.1)
= 1 - P[( - ) / < (12.1-12) /0.067 ]
= 1 - P(z <1.49 )
Using z table
= 1 - 0.9319
= 0.0681
probability= 0.0681
b.
=0.2/ 1=0.2
P( > 12.1) = 1 - P( < 12.1)
= 1 - P[( - ) / < (12.1-12) /0.2 ]
= 1 - P(z <0.5 )
Using z table
= 1 - 0.6915
= 0.3085
probability= 0.3085