Question

In: Statistics and Probability

A Bernoulli trial is repeated 525 times and the number of successes observed is 96. At...

A Bernoulli trial is repeated 525 times and the number of successes observed is 96.

At a confidence level of 97%, calculate the margin of error in the estimated proportion of successes.

Expert Solution

Solution :

Given that,

n = 525

x = 96

Point estimate = sample proportion = = x / n = 96/525=0.183

1 - = 1-0.183 =0.817

At 97% confidence level the z is ,

= 1 - 97% = 1 - 0.97 = 0.03

/ 2 = 0.03 / 2 = 0.015

Z/2 = Z0.015 = 2.170 ( Using z table )

Margin of error = E = Z/2 * $\sqrt$ ((( * (1 - )) / n)

= 2.170 ( $\sqrt$ ((0.183*0.817) / 525)

= 0.0366

At a confidence level of 97%, calculate the margin of error in the estimated proportion of successes. is 0.0366

orchestra answered 2 years ago

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