In: Statistics and Probability
A Bernoulli trial is repeated 525 times and the number of successes observed is 96.
At a confidence level of 97%, calculate the margin of error in the estimated proportion of successes.
Solution :
Given that,
n = 525
x = 96
Point estimate = sample proportion =
= x / n = 96/525=0.183
1 -
= 1-0.183 =0.817
At 97% confidence level the z is ,
= 1 - 97% = 1 - 0.97 = 0.03
/ 2 = 0.03 / 2 = 0.015
Z/2
= Z0.015 = 2.170 ( Using z table )
Margin of error = E = Z/2 *
(((
* (1 -
)) / n)
= 2.170 (((0.183*0.817)
/ 525)
= 0.0366
At a confidence level of 97%, calculate the margin of error in the estimated proportion of successes. is 0.0366