According to the 2016 CCSSE data from about 430,000 community college   students nationwide, about 13.5% of students reported that they “often” or “very often” come to class without completing readings or assignments.

Are the results similar at community colleges in California? Specifically, let’s test the claim that California students are different. Use a 5% level of significance.

Suppose that the CCSSE is given in California to a random sample of 500 students and 10.5% report that they “often” or “very often” come to class without completing readings or assignments.

a) State the hypotheses in words and write a sentence to explain what p represents.

b)Verify that the normal model is a good fit for the distribution of sample proportions.

c) Test the claim by a significance test( 6-steps, show all calculations)

d)State your conclusion.

The widths of the heads of fireworks on Dragon Island M= 91mm and standard deviation=23mm and have a normal distribution.

a. By law, fireworms in the smallest 10th percentile must be released if captured. Find the head width that represents the 10th percentile.

b. It appears only fireworks with head widths of 102mm to 119mm make reliable circus performers. What percentage of fireworks does this represent ?

c. Offers a reward for the largest 10% of fireworks on the island. What head width represents the 90th percentile ?

give an example of real-world research questions that would require you to do each of the following...

(a) determine whether a sample is different from a population

(b) whether two samples (i.e., groups) are different from each other.

Develop a random number generator for a Poisson distribution with mean = 10. Generate five values manually with a random number table. Please show work.

Why is the standard deviation of the bootstrapped distribution smaller than that of the sample?

1. You have a friend named Clarence who never heard of statistics before. Explain what statistics is and how it relates to today's world. Give examples.

2. You are given a list of cholesterol levels and asked to calculate the mean and median. What would make the median a better measure of central tendency than the mean?

3. What is the purpose of looking at Percentiles? Why would you choose this rather than analyzing the mean or median? Give examples.

Measure your own heart rate in beats per minute. Post your individual results and corresponding z-score using a population mean resting heart rate of 73 beats per minute and standard deviation of 8 beats per minute. Be sure to use the formula z equal fraction numerator Y minus italic mu over denominator italic sigma end fraction to calculate your z score. Use the StandardNormalZTables(1).pdf to find your resting heart rate percentile ranking. Do you think your resting hear rate is rare? For example: My resting heart rate is 64. My z score is -1.125 (use -1.13 for the table). My percentile rank is 12.92%. I do not think my resting heart rate is rare since it is less than 2 standard deviations from the mean.

Engineers concerned about a tower's stability have done extensive studies of its increasing tilt. Measurements of the lean of the tower over time provide much useful information. The following table gives measurements for the years 1975 to 1987. The variable "lean" represents the difference between where a point on the tower would be if the tower were straight and where it actually is. The data are coded as tenths of a millimeter in excess of 2.9 meters, so that the 1975 lean, which was 2.9644 meters, appears in the table as 644. Only the last two digits of the year were entered into the computer.

(b) What is the equation of the least-squares line? (Round your answers to three decimal places.)
y = _____ + _____x

What percent of the variation in lean is explained by this line? (Round your answer to one decimal place.)
%

Give a 99% confidence interval for the average rate of change (tenths of a millimeter per year) of the lean. (Round your answers to two decimal places.)
( _____ , _____ )

A traffic safety company publishes reports about motorcycle fatalities and helmet use. In the first accompanying data​ table, the distribution shows the proportion of fatalities by location of injury for motorcycle accidents. The second data table shows the location of injury and fatalities for 2068 riders not wearing a helmet.

Location of Injury   Probability   Frequency
Multiple Locations   0.570   1027
Head   0.310   869
Neck   0.030   40
Thorax   0.060   83
Abdomen/Lumbar/Spine   0.030   49

​(a) Does the distribution of fatal injuries for riders not wearing a helmet follow the distribution for all​ riders? Use

alphaαequals=0.050.05

level of significance. What are the null and alternative​ hypotheses?

A.

H0​: The distribution of fatal injuries for riders not wearing a helmet does not follow the same distribution for all other riders.

H1​: The distribution of fatal injuries for riders not wearing a helmet does follow the same distribution for all other riders.

B.

H0​: The distribution of fatal injuries for riders not wearing a helmet follows the same distribution for all other riders.

H1​: The distribution of fatal injuries for riders not wearing a helmet does not follow the same distribution for all other riders. Your answer is correct.

C.

None of these.

Compute the expected counts for each fatal injury.

​(Round to two decimal places as​ needed.)

how one way of central tendency is not always the “best” way to get the one in the middle? thank you

More than 40 million Americans are estimated to have at least one outstanding student loan to help pay college expenses ("40 Million Americans Now Have Student Loan Debt", CNNMoney, September 2014). Not all of these graduates pay back their debt in satisfactory fashion. Suppose that the following joint probability table shows the probabilities of student loan status and whether or not the student had received a college degree. If needed, round your answers to three decimal digits.

Perform the appropriate hypothesis test for the problem. State the hypotheses, identify the claim, compute the test statistic and P-value, make a decision, and write the interpretation in terms of the claim. For consistency, use a significance level of 0.05 for the problem.

Two brands of components are compared by installing one of each brand randomly in the right and left sides of several randomly selected machines and noting the total machine operation time (in minutes) until the component needs to be replaced. Can you conclude that Brand 1 has a better mean lifetime based on the data below?

According to a survey in a​ country, 39​% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained. Complete parts​ (a) through​ (d) below. Click here to view the standard normal distribution table (page 1). LOADING... Click here to view the standard normal distribution table (page 2). LOADING... ​(a) Describe the sampling distribution of ModifyingAbove p with caret​, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of ModifyingAbove p with caret below. A. Not normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10 B. Approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis less than 10 C. Approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10 D. Not normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis less than 10 Determine the mean of the sampling distribution of ModifyingAbove p with caret. mu Subscript ModifyingAbove p with caret Baseline equals nothing ​(Round to two decimal places as​ needed.) Determine the standard deviation of the sampling distribution of ModifyingAbove p with caret. sigma Subscript ModifyingAbove p with caretequals nothing ​(Round to three decimal places as​ needed.) ​(b) What is the probability that in a random sample of 200 ​adults, more than 41​% do not own a credit​ card? The probability is nothing. ​(Round to four decimal places as​ needed.) Interpret this probability. If 100 different random samples of 200 adults were​ obtained, one would expect nothing to result in more than 41​% not owning a credit card. ​(Round to the nearest integer as​ needed.) ​(c) What is the probability that in a random sample of 200 ​adults, between 36​% and 41​% do not own a credit​ card? The probability is nothing. ​(Round to four decimal places as​ needed.) Interpret this probability. If 100 different random samples of 200 adults were​ obtained, one would expect nothing to result in between 36​% and 41​% not owning a credit card. ​(Round to the nearest integer as​ needed.) ​(d) Would it be unusual for a random sample of 200 adults to result in 72 or fewer who do not own a credit​ card? Why? Select the correct choice below and fill in the answer box to complete your choice. ​(Round to four decimal places as​ needed.) A. The result is not unusual because the probability that ModifyingAbove p with caret is less than or equal to the sample proportion is nothing​, which is greater than​ 5%. B. The result is unusual because the probability that ModifyingAbove p with caret is less than or equal to the sample proportion is nothing​, which is greater than​ 5%. C. The result is not unusual because the probability that ModifyingAbove p with caret is less than or equal to the sample proportion is nothing​, which is less than​ 5%. D. The result is unusual because the probability that ModifyingAbove p with caret is less than or equal to the sample proportion is nothing​, which is less than​ 5%.

A presidential candidate wants to test the null hypothesis that she has the same support rate in Virginia and in Maryland. In a random sample from Virginia, 307 among 642 asked would vote for this candidate. In a random sample from Maryland, 366 among 712 asked would vote for this candidate. Perform a 2-sided test. What is the p-value? Answer to three decimal places.