A baseball player has a lifetime batting average of 0.168. If, in a season, this player has 460 "at bats", what is the probability he gets 101 or more hits?
Probability of 101 or more hits =
Answer is not .0015 or .0019.
In: Statistics and Probability
The pH of a liquid is a measure of its acidity or alkalinity. Pure water was a pH of 7, which is neutral. Solutions with a pH less than 7 are acidic while solutions with a pH greater than 7 are alkaline. A biologist was interested in testing the purity of lake water in Florida. A random sample of 59 lakes was taken, and the pH of water in each lake was recorded. The sample of lakes had an average pH of 6.729 with a standard deviation of 1.827.
Using a significance level of 0.10, is there evidence the mean pH of Florida lakes is not neutral?
Ho:μ=7Ho:μ=7
Ha:μ<7Ha:μ<7
Ho:μ≠7Ho:μ≠7
Ha:μ=7Ha:μ=7
Ho:μ=7Ho:μ=7
Ha:μ>7Ha:μ>7
Ho:μ=7Ho:μ=7
Ha:μ≠7Ha:μ≠7
Based on the decision of your test and the sample selected, what can you conclude?
In: Statistics and Probability
According to U.S. News & World Report's publication America's Best Colleges, the average cost to attend the University of Southern California (USC) after deducting grants based on need is $26,950. Assume the population standard deviation is $7,800. Suppose that a random sample of 70 USC students will be taken from this population. Use z-table.
a. What is the value of the standard error of the mean?
(to nearest whole number)
b. What is the probability that the sample mean will be more than $26,950?
(to 2 decimals)
c. What is the probability that the sample mean will be within $750 of the population mean?
(to 4 decimals)
d. How would the probability in part (c) change if the sample size were increased to 160 ?
(to 4 decimals)
In: Statistics and Probability
High school diploma |
Associate degree |
x1=$36,875 |
x2=$44,900 |
s1=$5475 |
s2=$8580 |
n1=25 |
n2=16 |
(Note: Is this a z-test or a t-test? One sample, dependent sample or independent sample)
In: Statistics and Probability
Question 1
Researchers are interested in testing the effectiveness of a new immunosuppressive therapy to be used post-transplant to reduce graft failure in the host. Suppose researchers investigating this new therapy are concerned about the dangerous side-effects of the drug. For instance, participants that would like to enroll in the study are not allowed to already have diabetes, as the immunosuppressive agent has been found to drastically increase fasting glucose levels, which could be very dangerous for diabetics. This means, however, that participants that enter and are treated with the new drug may develop diabetes as time goes on. Suppose the following table addresses the incidence of diabetes in the study depending on treatment group.
Type II Diabetes |
No Type II Diabetes |
Total |
|
Investigational Drug |
41 |
27 |
68 |
Best standard of Care |
12 |
63 |
75 |
Total |
53 |
90 |
143 |
A) Calculate the incidence of diabetes in the group after the follow-up period.
B) Calculate the relative risk of diabetes due to the investigational drug in the study.
C) Carry out a formal chi-square test to determine if there is a significant difference in diabetes between the two groups. Write out your null and alternative hypotheses at the 0.05 alpha level.
Choose the most appropriate option
Option 1 A) Incidence group=22.06% B) RR=4.22 C) Ho: no association between treatment groups and type II diabetes in the source population Ha: association exists between the variables. Xi-Square stat=33.977 1 df Pvalue ~0 Reject the Ho that there is no association between treatment group and type II diabetes status. |
||
Option 2 A) Incidence group=37.06% B) RR=3.77 C) Ho: no association between treatment groups and type II diabetes in the source population Ha: association exists between the variables. Xi-Square stat=29.997 1 df Pvalue ~0 Reject the Ho that there is no association between treatment group and type II diabetes status. |
||
Option 3 A) Incidence group=22.16% B) RR=1.34 C) Ho: There is an association between treatment groups and type II diabetes in the source population Ha: no association exists between the variables. Xi-Square stat=17.22 2 df Pvalue ~0 Reject the Ho that there is an association between treatment group and type II diabetes status. |
In: Statistics and Probability
The Fox TV network is considering replacing one of its prime-time crime investigation shows with a new family-oriented comedy show. Before a final decision is made, network executives commission a sample of 490 viewers. After viewing the comedy, 420 indicated they would watch the new show and suggested it replace the crime investigation show.
a. Estimate the value of the population proportion. (Round the final answer to 3 decimal places.)
Estimate of proportion
b. Compute the standard error of the proportion. (Round the final answer to 3 decimal places.)
Standard error of the proportion
c. Develop a 95% confidence interval for the population proportion. (Round the final answers to 3 decimal places.)
The confidence interval is between and .
d. Interpret your findings. (Round the final answers to the nearest whole number.)
We are reasonably sure the population proportion is between and %.
In: Statistics and Probability
In: Statistics and Probability
The question to address is: “What have you learned about statistics?” In developing your responses, consider—at a minimum—and discuss the application of each of the course elements in analyzing and making decisions about data (counts and/or measurements).
In: Statistics and Probability
Consider the following data for the patients taking the drug (Ascorbic Acid).
Placebo | Drug | Sum | |
Cold | 36 | 87 | 123 |
NoCold | 224 | 333 | 557 |
Sum | 260 | 420 | 680 |
What is the probability that a patient has No Cold? Is this a marginal or joint probability?
a) 0.18 marginal
b) 0.62 marginal
c) 0.82 marginal
d) 0.82 joint
e) 0.86 joint
Question 15
What is the probability that a patient is taking Placebo and has No Cold? Is this a marginal or joint probability?
a) 0.86 joint
b) 0.33 joint
c) 0.33 marginal
d) 0.82 marginal
e) 0.82 joint
Question 16
What is the probability that a patient is taking Placebo or has No Cold and identify the correct formula for this kind of probability?
a) 0.92 F5c
b) 0.87 F5a
c) 0.33 F5c
d) 0.92 F5b
e) 0.87 F5b
Question 17
Find conditional probability P(No Cold | taking the drug), P(No Cold | taking Placebo), P(taking drug | No Cold) and identify the correct formula for this kind of probability?
a) 0.49, 0.33, 0.82 F5ef
b) 0.18, 0.62, 0.82 F5c
c) 0.6, 0.71, 0.79, F5ef
d) 0.79, 0.86, 0.6 F5g
e) 0.79, 0.86, 0.6 F5ef
Question 18
Based on answers to previous questions the row and column variables are ________ (a) independent (b) dependent (c) marginal (d) conditional (e) joint
a) marginal
b) joint
c) dependent
d) independent
e) conditional
In: Statistics and Probability
A recent study of two vendors of desktop personal computers reported that out of 895 units sold by Brand A, 118 required repair, while out of 711 units sold by Brand B, 98 required repair. Round all numeric answers to 4 decimal places.
1. Calculate the difference in the sample proportion for the two brands of computers, ?̂ ??????−?̂ ??????p^BrandA−p^BrandB = .
2. What are the correct hypotheses for conducting a hypothesis
test to determine whether the proportion of computers needing
repairs is different for the two brands.
A. ?0:??−??=0H0:pA−pB=0,
??:??−??<0HA:pA−pB<0
B. ?0:??−??=0H0:pA−pB=0,
??:??−??≠0HA:pA−pB≠0
C. ?0:??−??=0H0:pA−pB=0,
??:??−??>0HA:pA−pB>0
3. Calculate the pooled estimate of the sample proportion, ?̂ p^ =
4. Is the success-failure condition met for this scenario?
A. Yes
B. No
5. Calculate the test statistic for this hypothesis test. ? z t X^2 F =
6. Calculate the p-value for this hypothesis test, p-value = .
7. Based on the p-value, we have:
A. little evidence
B. strong evidence
C. some evidence
D. very strong evidence
E. extremely strong evidence
that the null model is not a good fit for our observed data.
8. Compute a 99 % confidence interval for the difference ?̂ ??????−?̂ ??????p^BrandA−p^BrandB = ( , )
In: Statistics and Probability
In: Statistics and Probability
Let x be per capita income in thousands of dollars. Let y be the number of medical doctors per 10,000 residents. Six small cities in Oregon gave the following information about x and y. x 8.3 9.3 10.2 8.0 8.3 8.7 y 9.9 18.1 20.6 10.2 11.4 13.1 Complete parts (a) through (e), given Σx = 52.8, Σy = 83.3, Σx2 = 468, Σy2 = 1255.59, Σxy = 750.81, and r ≈ 0.974. (a) Draw a scatter diagram displaying the data. Selection Tool Line Ray Segment Circle Vertical Parabola Horizontal Parabola Point No Solution Help 123456789101112345678910111213141516171819202122 Clear Graph Delete Layer Fill WebAssign Graphing Tool Graph LayersToggle Open/Closed After you add an object to the graph you can use Graph Layers to view and edit its properties. (b) Verify the given sums Σx, Σy, Σx2, Σy2, Σxy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.) Σx = Σy = Σx2 = Σy2 = Σxy = r = (c) Find x, and y. Then find the equation of the least-squares line y hat = a + bx. (Round your answers for x and y to two decimal places. Round your answers for a and b to three decimal places.) x = y = y hat = + x (d) Graph the least-squares line. Be sure to plot the point (x, y) as a point on the line. WebAssign Plot WebAssign Plot WebAssign Plot WebAssign Plot (e) Find the value of the coefficient of determination r2. What percentage of the variation in y can be explained by the corresponding variation in x and the least-squares line? What percentage is unexplained? (Round your answer for r2 to three decimal places. Round your answers for the percentages to one decimal place.) r2 = explained % unexplained % (f) Suppose a small city in Oregon has a per capita income of 9.2 thousand dollars. What is the predicted number of M.D.s per 10,000 residents? (Round your answer to two decimal places.) M.D.s per 10,000 residents
In: Statistics and Probability
Let x be the age in years of a licensed automobile driver. Let y be the percentage of all fatal accidents (for a given age) due to speeding. For example, the first data pair indicates that 34% of all fatal accidents of 17-year-olds are due to speeding. x 17 27 37 47 57 67 77 y 34 22 22 12 10 7 5 Complete parts (a) through (e), given Σx = 329, Σy = 112, Σx2 = 18,263, Σy2 = 2442, Σxy = 3974, and r ≈ −0.956. (a) Draw a scatter diagram displaying the data. Selection Tool Line Ray Segment Circle Vertical Parabola Horizontal Parabola Point No Solution Help 5101520253035404550556065707580510152025303540 Clear Graph Delete Layer Fill WebAssign Graphing Tool Graph LayersToggle Open/Closed After you add an object to the graph you can use Graph Layers to view and edit its properties. (b) Verify the given sums Σx, Σy, Σx2, Σy2, Σxy and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.) Σx = Σy = Σx2 = Σy2 = Σxy = r = (c) Find x, and y. Then find the equation of the least-squares line y hat = a + bx. (Round your answers for x and y to two decimal places. Round your answers for a and b to three decimal places.) x = y = y hat = + x (d) Graph the least-squares line. Be sure to plot the point (x, y) as a point on the line. WebAssign Plot WebAssign Plot WebAssign Plot WebAssign Plot (e) Find the value of the coefficient of determination r2. What percentage of the variation in y can be explained by the corresponding variation in x and the least-squares line? What percentage is unexplained? (Round your answer for r2 to three decimal places. Round your answers for the percentages to one decimal place.) r2 = explained % unexplained % (f) Predict the percentage of all fatal accidents due to speeding for 35-year-olds. (Round your answer to two decimal places.) % Need Help?
In: Statistics and Probability
The Sugar Producers Association wants to estimate the mean yearly sugar consumption. A sample of 22 people reveals the mean yearly consumption to be 32 kilograms (kg) with a standard deviation of 10 kg. Assume a normal population.
a-1. What is the value of the population mean?
Population mean (Click to select) Unknown 32 42
a-2. What is the best estimate of this value?
Estimate value
b-1. Explain why we need to use the t distribution.
(Click to select) Use the t distribution as the population standard deviation is known. Use the t distribution as the population standard deviation is unknown. Use the t distribution as the population mean is known.
b-2. What assumption do you need to make?
(Click to select) We must assume that the population is normally distributed. We must assume that the population is binomially distributed. We must assume that the population is not normally distributed.
c. For a 90% confidence interval, what is the value of t? (Round the final answer to 3 decimal places.)
Value of t
d. Develop the 90% confidence interval for the population mean. (Round the final answers to 3 decimal places.)
Confidence interval for the population mean is and .
e. Would it be reasonable to conclude that the population mean is 37 kg?
(Click to select) No Yes
That value is (Click to select) not reasonable reasonable because it is (Click to select) inside not inside the interval.
In: Statistics and Probability
The Fox TV network is considering replacing one of its prime-time crime investigation shows with a new family-oriented comedy show. Before a final decision is made, network executives commission a sample of 400 viewers. After viewing the comedy, 250 indicated they would watch the new show and suggested it replace the crime investigation show.
a. Estimate the value of the population proportion. (Round the final answer to 3 decimal places.)
Estimate of proportion
b. Compute the standard error of the proportion. (Round the final answer to 3 decimal places.)
Standard error of the proportion
c. Develop a 99% confidence interval for the population proportion. (Round the final answers to 3 decimal places.)
The confidence interval is between and .
d. Interpret your findings. (Round the
final answers to the nearest whole number.)
We are reasonably sure the population proportion is between and %.
In: Statistics and Probability