Questions
3. An engineer wanted to determine how the weight of a car (kilograms), ?, affects fuel...

3. An engineer wanted to determine how the weight of a car (kilograms), ?, affects fuel consumption (kilometers per litre), ?. The weights and fuel consumption for a random sample of 10 cars were recorded. Refer to the regression results from Excel.

Regression Statistics

Multiple R

0.84157604

R Square

0.708250231

Adjusted R Square

0.671781509

Standard Error

0.712010044

Observations

10

  

Coefficients

Standard Error

t-Stat

P-Value

Lower 95%

Upper 95%

Intercept

15.883033

1.680071

9.453785

0.000013

12.008782

19.757285

X-Variable 1

-0.004384

0.000995

(?)

0.002266

-0.006679

-0.002090

a) Write the equation of the estimated least-squares regression line.

b) Test whether a linear relationship exists between weight of a car and fuel consumption at the
? = 0.01 level of significance. Use the critical value method.

c) Use the Excel output to write a 95% confidence interval for the slope of the true least-squares regression line. Interpret the result. Write a descriptive statement that could be easily understood by someone who is not in this statistics class.

d) A 95% prediction interval for ? = 1900 is 5.83 to 9.28. Interpret this result. Write a descriptive
statement that could be easily understood by someone who is not in this statistics class.

In: Statistics and Probability

Cynthia is a rideshare driver, and she often starts and stops her car. Each time Cynthia...

Cynthia is a rideshare driver, and she often starts and stops her car. Each time Cynthia starts her car it either runs or stalls. If her car stalls when she starts it, then it always runs the next time she starts it. If her car runs when she starts it, then next time it is ten times as likely to stall as it is to run.

How often in the long run does Cynthia's car run when she starts it? Answer with a fraction in lowest terms.

In: Statistics and Probability

Calculate each binomial probability: (a) Fewer than 5 successes in 11 trials with a 10 percent...

Calculate each binomial probability:

(a) Fewer than 5 successes in 11 trials with a 10 percent chance of success. (Round your answer to 4 decimal places.)

Probability =      

(b) At least 2 successes in 8 trials with a 30 percent chance of success. (Round your answer to 4 decimal places.)

Probability =   

(c) At most 10 successes in 18 trials with a 70 percent chance of success. (Round your answer to 4 decimal places.)

Probability =             

In: Statistics and Probability

A person has a net asset of $1 million, including a $300,000 net equity of a...

A person has a net asset of $1 million, including a $300,000 net equity of a house (market value of the house – mortgage). Specifically, the house has a market value of $500,000 including $300,000 for the structure and $200,000 for the land, and a mortgage of $200,000. The person plans to buy $300,000 fire insurance for full coverage of the house. For simplicity, assume that each year the house has a 1% probability of being totally destroyed by fire and a 99% probability of no damage occurring to the house. The person’s utility for money is approximately proportional to the quartic root of money with U($100,000,000)=100 and U($0)=0.

7a.(5 points) Draw the decision tree for the person’s decision of buying or not buying the insurance.

7b.(10 points) Determine the maximum insurance premium IP the person would be willing to pay.

7c. (5 points) What is the risk premium at the maximum IP?

Determine the maximum insurance premium the person would be willing to pay for a $200,000 insurance just to cover the mortgage.

(Hint: in this case, the house is under-insured. In other words, with the $200,000 insurance, if the house is totally destroyed by fire, the person will suffer a loss in the net asset because the insurance covers only the mortgage not the full net equity of the house, and the maximum insurance premium the person would be willing to pay will need to be determined through numerical iterations).

In: Statistics and Probability

Sheets of aluminum from a supplier have a thickness that is normally distributed with a mean...

Sheets of aluminum from a supplier have a thickness that is normally distributed with a mean of 50 mm and a standard deviation of 4 mm (call this random variable X). Your company compresses the aluminum with a tool that is normally distributed with a mean of 20 mm and a standard deviation of 3 mm (call this random variable Y). You are interested in the random variable V = X – Y, the random variable V is the final aluminum thickness.

1. What is the probability that the outputted aluminum (that is, V), will be between 25 mm and 32 mm?

2. What is the probability that the outputted aluminum (that is, V), will be between 26.5 mm and 33.5 mm?

3. If the company had the choice between compressing aluminum to between 25-32 mm or 26.5-33.5 mm, then which is preferred (or neither)?

4. In one or two sentences, why is one preferred (if either) over the other [continuation of 3.3]; if neither are preferred, then why?

In: Statistics and Probability

Given the transition matrix P for a Markov chain, find the stable vector W. Write entries...

Given the transition matrix P for a Markov chain, find the stable vector W. Write entries as fractions in lowest terms.

P= 0.5 0 0.5
    0.2 0.2 0.6
      0    1     0

In: Statistics and Probability

An orange juice producer buys oranges from a large orange grove that has one variety of...

An orange juice producer buys oranges from a large orange grove that has one variety of orange. The amount of juice squeezed from these oranges is approximately normally​ distributed, with a mean of 4.40 ounces and a standard deviation of 0.32 ounce. Suppose that you select a sample of 16 oranges.

a. What is the probability that the sample mean amount of juice will be at least 4.27 ​ounces?

b. The probability is 72​% that the sample mean amount of juice will be contained between what two values symmetrically distributed around the population​ mean?

c. The probability is 74​% that the sample mean amount of juice will be greater than what​ value?

In: Statistics and Probability

What is a sampling distribution of means? How is it created and what is it used...

What is a sampling distribution of means? How is it created and what is it used for?

In: Statistics and Probability

A recent study of 3100 children randomly selected found 20​% of them deficient in vitamin D....

A recent study of 3100 children randomly selected found 20​% of them deficient in vitamin D.

​a) Construct the​ 98% confidence interval for the true proportion of children who are deficient in vitamin D.

left parenthesis nothing comma nothing right parenthesis,

​(Round to three decimal places as​ needed.)

In: Statistics and Probability

A hospital conducted a study of the waiting time in its emergency room. The hospital has...

A hospital conducted a study of the waiting time in its
emergency
room. The hospital has a main campus and three
satellite
locations. Management had a business objective of reducing
waiting time for emergency room cases that did not require
immediate attention. To study this, a random sample of 15 emergency
room cases that did not require immediate attention at each
location were selected on a particular day, and the waiting times
(measured from check-in to when the patient was called into the
clinic area) were collected and stored in ERWaiting .
a. At the 0.05 level of significance, is there evidence of a difference
in the mean waiting times in the four locations?

Data Is Below:

Main Satellite 1 Satellite 2 Satellite 3
120.08 30.75 75.86 54.05
81.90 61.83 37.88 38.82
78.79 26.40 68.73 36.85
63.83 53.84 51.08 32.83
79.77 72.30 50.21 52.94
47.94 53.09 58.47 34.13
79.88 27.67 86.29 69.37
48.63 52.46 62.90 78.52
55.43 10.64 44.84 55.95
64.06 53.50 64.17 49.61
64.99 37.28 50.68 66.40
53.82 34.31 47.97 76.06
62.43 66.00 60.57 11.37
65.07 8.99 58.37 83.51
81.02 29.75 30.40 39.17

In: Statistics and Probability

Measuring the height of a California redwood tree is very difficult because these trees grow to...

Measuring the height of a California redwood tree is very
difficult because these trees grow to heights of over 300 feet. People
familiar with these trees understand that the height of a California
redwood tree is related to other characteristics of the tree,
including the diameter of the tree at the breast height of a person.
The data in Redwood represent the height (in feet) and diameter
(in inches) at the breast height of a person for a sample of 21 California
redwood trees.
a. Assuming a linear relationship, use the least-squares method
to compute the regression coefficients b0 and b1. State the regression
equation that predicts the height of a tree based on the
tree’s diameter at breast height of a person.
b. Interpret the meaning of the slope in this equation.
c. Predict the mean height for a tree that has a breast height diameter
of 25 inches.
d. Interpret the meaning of the coefficient of determination in this
problem.
e. Perform a residual analysis on the results and determine the adequacy
of the model.

Data Is Below:

Height Diameter at breast height Bark thickness
122.0 20 1.1
193.5 36 2.8
166.5 18 2.0
82.0 10 1.2
133.5 21 2.0
156.0 29 1.4
172.5 51 1.8
81.0 11 1.1
148.0 26 2.5
113.0 12 1.5
84.0 13 1.4
164.0 40 2.3
203.3 52 2.0
174.0 30 2.5
159.0 22 3.0
205.0 42 2.6
223.5 45 4.3
195.0 54 4.0
232.5 39 2.2
190.5 36 3.5
100.0 8 1.4

In: Statistics and Probability

You want to know the mean number of customers that enter a store per hour. Using...

You want to know the mean number of customers that enter a store per hour. Using data collected over the last month, we have

* a 90% confidence interval (C.I.) for the population mean is (17.11, 24.75)
* a 99% C.I. of (14.95, 26.91)
* a 95% C.I. of (16.38,25.48)
For a hypothesis test of H0: μ = 25, in what range will the P value be?

Explain. Just use the CI’s to determine the range p-value should be in.

In: Statistics and Probability

In a random sample of 120 car batteries produced by a special method, the sample average...

In a random sample of 120 car batteries produced by a special method, the sample average lifetime was 135 hours and the sample standard deviation was 12 hours. An engineer claims that the mean lifetime is between 132.452 and 137.548 hours. Assume data is normally distributed.

(a) What level of confidence can this statement be made with?

(b) Create a confidence interval for the population variance and explain how you did it. State your conclusion.

In: Statistics and Probability

To properly treat patients, drugs prescribed by physicians must have a potency that is accurately defined....

To properly treat patients, drugs prescribed by physicians must have a potency that is accurately defined. Consequently, not only must the distribution of potency values for shipments of a drug have a mean value as specified on the drug's container, but also the variation in potency must be small. Otherwise, pharmacists would be distributing drug prescriptions that could be harmfully potent or have a low potency and be ineffective. A drug manufacturer claims that its drug is marketed with a potency of 5 ± 0.1 milligram per cubic centimetre (mg/cc). A random sample of four containers gave potency readings equal to 4.93, 5.08, 5.03, and 4.89 mg/cc.

(a) Do the data present sufficient evidence to indicate that the mean potency differs from 5 mg/cc? (Use α = 0.05. Round your answers to three decimal places.)

1-2. Null and alternative hypotheses:

H0: μ = 5 versus Ha: μ < 5H0: μ ≠ 5 versus Ha: μ = 5    H0: μ = 5 versus Ha: μ > 5H0: μ < 5 versus Ha: μ > 5H0: μ = 5 versus Ha: μ ≠ 5


3. Test statistic:    t =  

4. Rejection region: If the test is one-tailed, enter NONE for the unused region.

t >
t <


5. Conclusion:

H0 is not rejected. There is insufficient evidence to indicate that the mean potency differs from 5 mg/cc.H0 is not rejected. There is sufficient evidence to indicate that the mean potency differs from 5 mg/cc.    H0 is rejected. There is sufficient evidence to indicate that the mean potency differs from 5 mg/cc.H0 is rejected. There is insufficient evidence to indicate that the mean potency differs from 5 mg/cc.


(b) Do the data present sufficient evidence to indicate that the variation in potency differs from the error limits specified by the manufacturer? (HINT: It is sometimes difficult to determine exactly what is meant by limits on potency as specified by a manufacturer. Since it implies that the potency values will fall into the interval 5.0 ± 0.1 mg/cc with very high probability—the implication is always—let us assume that the range 0.2; or (4.9 to 5.1), represents 6σ, as suggested by the Empirical Rule. Note that letting the range equal 6σ rather than 4σ places a stringent interpretation on the manufacturer's claim. We want the potency to fall into the interval

5.0 ± 0.1

with very high probability.) (Use α = 0.05. Round your answers to three decimal places.)

1-2. Null and alternative hypotheses:

H0: σ2 = 0.0011 versus Ha: σ2 < 0.0011H0: σ2 > 0.0011 versus Ha: σ2 < 0.0011    H0: σ2 = 0.2 versus Ha: σ2 ≠ 0.2H0: σ2 = 0.0011 versus Ha: σ2 > 0.0011H0: σ2 = 0.2 versus Ha: σ2 > 0.2


3. Test statistic:    χ2 =  

4. Rejection region: If the test is one-tailed, enter NONE for the unused region.

χ2 >
χ2 <


5. Conclusion:

H0 is rejected. There is insufficient evidence to indicate that the variation in potency differs from the specified error limits.H0 is rejected. There is sufficient evidence to indicate that the variation in potency differs from the specified error limits.    H0 is not rejected. There is insufficient evidence to indicate that the variation in potency differs from the specified error limits.H0 is not rejected. There is sufficient evidence to indicate that the variation in potency differs from the specified error limits.

In: Statistics and Probability

You are a public health nurse that is interested in comparing the total blood cholesterol levels...

You are a public health nurse that is interested in comparing the total blood cholesterol levels in clients from different census tracts in the city that are enrolled in a community-based lifestyle program offer by the Public Health Department. Previous research has shown that cholesterol levels are generally normally distributed, and you have no reason to believe that the variances in cholesterol levels would differ across census tracts. The table below provides the data that you collected on cholesterol levels in clients enrolled in your program from four census tracts in the city. Assuming a 0.05 level of significance, can you conclude that cholesterol levels differ across the census tracts? If there is a difference, which census tracts differ from the others?

Area A

Area B

Area C

Area D

96

120

138

101

126

122

139

104

166

128

140

104

168

131

140

107

173

132

141

108

178

147

159

122

190

148

166

125

194

149

172

136

195

151

176

139

198

160

180

149

212

160

182

160

212

162

185

162

213

164

188

162

215

165

188

168

216

174

192

171

227

184

194

173

185

194

174

188

200

175

192

202

180

194

203

182

197

206

182

198

210

184

201

215

184

221

220

190

224

222

191

230

224

192

242

230

193

250

231

194

251

232

195

233

200

237

206

243

207

245

207

263

209

274

210

294

212

307

215

327

221

224

227

229

231

239

241

248

262

317

In: Statistics and Probability