•  Complete a hypothesis test involving your independent variable. Test the claim

  that the mean of your independent variable is different then you guess (seethe “Set-Up” section of your project for your guess), using  = 0.05.
  Note: Because Minitab is using the same screen to perform both C.I. and H.T., Minitab is asking you to set (1-), the level of confidence and not  the level of significance of the test. If you want to perform a test at the 0.05 level, you will need to enter 0.95 in Minitab.

•  State your decision and conclusion using a full sentence and the right units.

•  Complete a hypothesis test involving your dependent variable. Test the claim that the mean of your dependent variable is smaller than your guess (see the

  “Set-Up” section of your project for your guess), using  = 0.01.
  Note: Because Minitab is using the same screen to perform both C.I. and H.T., Minitab is asking you to set (1-), the level of confidence and not  the level of significance of the test. If you want to perform a test at the 0.01 level, you will need to enter 0.99 in Minitab.

•  State your decision and conclusion using a full sentence and the right units.

data is as follows:

independent is time, temp is dependent

time temp

1 39

2 53

3 48

4 43

5 45

6 60

7 66

8 66

9 63

10 45

11 42

12 73

13 65

14 45

15 45

16 53

17 61

18 75

19 66

20 46

21 56

22 61

23 75

24 55

25 63

26 68

27 46

28 50

29 50

30 53

1) According to the Centers for Disease Control and Prevention (CDC), the mean total cholesterol level for persons 20 years of age and older in the United States from 2007–2010 was 197 mg/dL. a. What is the probability that a randomly selected adult from the population will have a total cholesterol level of less than 183 mg/dL? Use a standard deviation of 35 mg/dL and assume that the cholesterol levels for the population are normally distributed. b. What is the probability that a randomly selected sample of 150 adults from the population will have a mean total cholesterol level of less than 183 mg/dL? Use a standard deviation of 35 mg/dL.

1. It is claimed that the proportion of male golfers is more than 0.4 (40%).

1. State the null and alternate hypothesis that would be used to check this claim

2. Suppose a sample is taken and the requirements are met. The results of the analysis say reject the hypothesis at the 5% level of significance. Write the interpretation of this hypothesis test.

An exercise science major wants to try to use body weight to predict how much someone can bench press. He collects the data shown below on 30 male students. Both quantities are measured in pounds.

b) Compute a 95% confidence interval for the average bench press of 150 pound males. What is the lower limit? Give your answer to two decimal places.  

c) Compute a 95% confidence interval for the average bench press of 150 pound males. What is the upper limit? Give your answer to two decimal places.

d) Compute a 95% prediction interval for the bench press of a 150 pound male. What is the lower limit? Give your answer to two decimal places.

e) Compute a 95% prediction interval for the bench press of a 150 pound male. What is the upper limit? Give your answer to two decimal places.

A marketing researcher wants to estimate the mean amount spent​ ($) on a certain retail website by members of the​ website's premium program. A random sample of 99 members of the​ website's premium program who recently made a purchase on the website yielded a mean of ​$1700 and a standard deviation of ​$150.

Complete parts​ (a) and​ (b) below.

a. Construct a 90​%confidence interval estimate for the mean spending for all shoppers who are members of the​ website's premium program.

b. Interpret the interval of (a)

nfant mortality rate is defined as the number of babies that die between birth and age 1 per 1000 live births. For example, an infant mortality rate of 23.4 means that for every 1000 babies born 23.4 will die before age 1. We are using rates in this project because it allows us to compare regions with different population sizes.

1. Provide descriptive statistics (Mean, median, variance, standard deviation, and the five number summary) for infant mortality rate for each region.

2. Provide descriptive statistics (Mean, median, variance, standard deviation, and the five number summary) for under five mortality rate for each region.

3. Construct a side-by-side box plot for infant mortality rate and region. Please compare similarities or dissimilarities among the regions.

4. Construct a 95% confidence interval for the average infant mortality rate. Be sure to write a statement summarizing your findings

5. Construct a 95% confidence interval for the average under-five mortality rate. Be sure to write a statement summarizing your findings.

6. Test if the African average infant mortality rate is different from 62.56 using the population standard deviation 27.91 and normal distribution for ?=0.05.

Please provide a answer to 6, I believe its reject the null please correct me and in regards to number 3. Please provide a box plot that does not include any personal markings. Thank you for all the help.

1. A coffee machine dispenses 6 fluid ounces of coffee into a paper cup. Previous studies have shown that the amount dispensed is a normal distribution. A random sample of 15 cups is obtained where the standard deviation, s, is 0.154.

1. Determine if the requirements are met to compute a confidence interval for the true standard deviation, σ, of amounts of coffee being dispensed. List each requirement and state information given to support each one.

2. If the requirements are met, use StatCruch to find a 95% confidence interval and write the interpretation of the confidence interval for the population standard deviation.

Suppose that in a random selection of

100100

colored​ candies,

2424​%

of them are blue. The candy company claims that the percentage of blue candies is equal to

2727​%.

Use a

0.050.05

significance level to test that claim.

Given X + Y has a normal distribution, prove that X and Y each have a normal distribution if X and Y are iid random variables

The average number of pages for a simple random sample of 40 physics textbooks is 435. The average number of pages for a simple random sample of 30 mathematics textbooks is 410. Assume that all page length for each types of textbooks is normally distributed. The standard deviation of page length for all physics textbooks is known to be 55, and the standard deviation of page length for all mathematics textbooks is known to be 55. Part One: Assuming that on average, mathematics textbooks and physics textbooks have the same number of pages, what is the probability of picking samples of these sizes and getting a sample mean so much higher for the physics textbooks (one-sided p-value, to four places)?WebAssign will check your answer for the correct number of significant figures. The above p-value comes from a test-statistic of z=WebAssign will check your answer for the correct number of significant figures. (enter number without sign).

During the 2014-2015 NBA season, Stephen Curry of the Golden State Warriors attempted 646 three-point baskets and made 286. He also attempted 1,341 two-point baskets, making 653

of these. Use these counts to determine the probabilities for the following questions.

(a) Let the random variable X denote the result of a two- point attempt. X is either 0 or 2, depending on whether the basket is made. Find the expected value and variance of

X

b) Let a second random variable Y denote the result of a three- point attempt. Find the expected value and variance of Y

.

.

It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet. A transportation researcher wants to determine if the statement made in the advertisement is false. She randomly test drives 37 small cars at 65 miles per hour and records the braking distance. The sample average braking distance is computed as 111 feet. Assume that the population standard deviation is 21 feet. (You may find it useful to reference the appropriate table: z table or t table) a. State the null and the alternative hypotheses for the test. H0: μ = 120; HA: μ ≠ 120 H0: μ ≥ 120; HA: μ < 120 H0: μ ≤ 120; HA: μ > 120 b-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) b-2. Find the p-value. 0.01 p-value < 0.025 0.025 p-value < 0.05 0.05 p-value < 0.10 p-value 0.10 p-value < 0.01 c. Use α = 0.01 to determine if the average breaking distance differs from 120 feet.

Study Aim to determine the effect of four different types of tips in a hardness tester on the observed hardness of a metal alloy. Four Specimen of the alloy were obtained, and each tip was tested once on each specimen, producing the following data

a) Perform Anova using Minitab and present the table - please provide us with Minitab table?

b) is there an effect of the type of tips on the hardness.

c) Use fisher LSD to investigate the difference between the tips?

You wish to test the following claim (Ha) at a significance level of α=0.10.

      Ho:p1=p2
      Ha:p1<p2

You obtain a sample from the first population with 193 successes and 355 failures. You obtain a sample from the second population with 303 successes and 464 failures. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution.

What is the critical value for this test? (Report answer accurate to three decimal places.)
critical value =

What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =

The test statistic is...

• in the critical region
• not in the critical region

This test statistic leads to a decision to...

• reject the null
• accept the null
• fail to reject the null

As such, the final conclusion is that...

• There is sufficient evidence to warrant rejection of the claim that the first population proportion is less than the second population proportion.
• There is not sufficient evidence to warrant rejection of the claim that the first population proportion is less than the second population proportion.
• The sample data support the claim that the first population proportion is less than the second population proportion.
• There is not sufficient sample evidence to support the claim that the first population proportion is less than the second population proportion.