The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is registered to vote. Suppose that 649 employed persons and 666 unemployed persons are independently and randomly selected, and that 364 of the employed persons and 299 of the unemployed persons have registered to vote. Can we conclude that the percentage of employed workers ( p1 ), who have registered to vote, exceeds the percentage of unemployed workers ( p2 ), who have registered to vote? Use a significance level of α=0.05 for the test.
Step 2 of 6:
Find the values of the two sample proportions, p^1 and p^2. Round your answers to three decimal places.
In: Statistics and Probability
A study of a disease reveals that there is an average of 1 case every 22 square miles. Residents of a town that has an area of 10 square miles are concerned because there are two cases in their area. The state’s Department of Health has decided to investigate further if the probability of getting two or more cases in this town is less than 0.05. Does the Department of Health investigate further?
In: Statistics and Probability
1) assume that when adults with smartphones are randomly selected, 48% use them in meetings or classes. If 6 adult smartphone users are randomly selected, find the probability that at least 3 of them use their smartphones in meetings or classes the probability is ? 2)
assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.25 probability that a pea has green pods. Assume that the offspring peas are randomly selected in groups of 30. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of peas with green pods in the groups of 30. The value of the mean is muequals nothing peas. (Type an integer or a decimal. Do not round.) The value of the standard deviation is sigmaequals nothing peas. (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of nothing peas or fewer are significantly low. (Round to one decimal place as needed.) Values of nothing peas or greater are significantly high. (Round to one decimal place as needed.) c. Is a result of 2 peas with green pods a result that is significantly low? Why or why not? 3)
Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes. If 9 adult smartphone users are randomly selected, find the probability that at least 5 of them use their smartphones in meetings or classes. The probability is
In: Statistics and Probability
In: Statistics and Probability
2. A study on wounds involved subjecting 18 randomly selected anaesthetized crested newts to a razor cut. The healing velocities of the cuts in micrometeres per hour for each newt were 29 27 34 40 22 28 14 35 26 35 12 30 23 18 11 22 23 33
(a) It is believed that the typical wound-healing velocity for crested newts is 30 micrometres/hour. Carry out a test to see if there is any evidence against this claim at level 0.05. Be sure to check all assumptions that you can check.
(b) What type of error (Type 1 or Type 2) could you be making from your conclusion in (a)? Describe that error in the context of the question.
(c) Carry out the test from (a) at level 0.01 using an appropriate condence interval.
In: Statistics and Probability
IAB conducted a study of U.S. online adults that included 416 tablet owners. The study found that 221 tablet owners use their tablet while watching TV, TV Experience - Attitudes and Usage across Multiple Screens - The authors of the report imply that the survey proves that more than half of all tablet owners use their tablet while watching TV at least once per day.
In: Statistics and Probability
A gender-selection technique is designed to increase the likelihood that a baby will be a girl. In the results of the gender-selection technique,
831831
births consisted of
426426
baby girls and
405405
baby boys. In analyzing these results, assume that boys and girls are equally likely.a. Find the probability of getting exactly
426426
girls in
831831
births.b. Find the probability of getting
426426
or more girls in
831831
births. If boys and girls are equally likely, is
426426
girls in
831831
births unusually high?
c. Which probability is relevant for trying to determine whether the technique is effective: the result from part (a) or the result from part (b)?
d. Based on the results, does it appear that the gender-selection technique is effective?
a.
The
probability of getting exactly
426426
girls in
831831
births is
nothing .
(Round to four decimal places as needed.)
b.
The
probability of getting
426426
or more girls in
831831
births is
nothing .
(Round to four decimal places as needed.)
If boys and girls are equally likely, is
426426
girls in
831831
births unusually high?
A.
Yes, because
426426
girls in
831831
births is far from what is expected, given the probability of having a girl or a boy.
B.
Yes, because
426426
girls in
831831
births is not far from what is expected, given the probability of having a girl or a boy.
C.
No, because
426426
girls in
831831
births is far from what is expected, given the probability of having a girl or a boy.
D.
No, because
426426
girls in
831831
births is not far from what is expected, given the probability of having a girl or a boy.
c. Which probability is relevant for trying to determine whether the technique is effective, the result from part (a) or the result from part (b)?
A.
The results from part (a) and part (b) are equal, so they are equally relevant.
B.
The result from part (b) is more relevant, because one wants the probability of a result that is at least as extreme as the one obtained.
C.
Neither of the results are relevant.
D.
The result from part (a) is more relevant, because one wants the probability of a result that is exactly equal to the one obtained.
d. Based on the results, does it appear that the gender-selection technique is effective?
A.
YesYes,
because the probability of having
426426
or more girls in
831831
births
isnbsp not nbsp not unlikely,
and thus,
isnbsp not nbsp not attributable
to random chance.
B.
YesYes,
because the probability of having
426426
or more girls in
831831
births
isnbsp unlikely,
and thus,
isnbsp not nbsp not attributable
to random chance.
C.
NoNo,
because the probability of having
426426
or more girls in
831831
births
isnbsp unlikely,
and thus,
isnbsp attributable
to random chance.
D.
NoNo,
because the probability of having
426426
or more girls in
831831
births
isnbsp not nbsp not unlikely,
and thus,
isnbsp attributable
to random chance.
More
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Click to select your answer(s).
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In: Statistics and Probability
In a study of red/green color blindness, 900 men and 2550 women
are randomly selected and tested. Among the men, 80 have red/green
color blindness. Among the women, 6 have red/green color blindness.
Test the claim that men have a higher rate of red/green color
blindness.
The test statistic is
The p-value is
Is there sufficient evidence to support the claim that men have a
higher rate of red/green color blindness than women using the 0.01%
significance level?
A. No
B. Yes
2. Construct the 99% confidence interval for the difference between
the color blindness rates of men and women.
<(p1−p2)<
Which of the following is the correct interpretation for your
answer in part 2?
A. We can be 99% confident that the difference
between the rates of red/green color blindness for men and women
lies in the interval
B. We can be 99% confident that that the
difference between the rates of red/green color blindness for men
and women in the sample lies in the interval
C. There is a 99% chance that that the difference
between the rates of red/green color blindness for men and women
lies in the interval
D. None of the above
In: Statistics and Probability
The distribution of pregnancy lengths of a certain mammal is
known to be right skewed with a population mean of 170 days and a
population standard deviation of 100 days.
a. Suppose four random samples with different sample size are drawn
from this distribution and the sample mean for each is calculated.
The same means were 145,169.8,183.3,175. Match the appropriate
sample size below with each sample mean, using the Law of Large
Numbers.
Sample Size 2..... Sample Mean =
Sample Size 20.... Sample Mean =
Sample Size 50.... Sample Mean =
Sample Size 200... Sample Mean =
b. Suppose we repeatedly take samples of size 100 from the
population distribution, calculate a sample mean each time, and
plot those sample means in a histogram. The histogram we created
would be an example of a --- sampling distribution
variable population distribution . According to the central limit
theorem, the histogram would have a shape that is
approximately --- right skewed normal left skewed , with
mean (give a number) and standard
deviation (give a number). The standard deviation of the
statistic under repeated sampling is called the ---
standard error absolute error deviation absolute deviation . The
middle 95% of the histogram we created lies
between and (give numbers for both blanks
with the smaller number listed first).
c. Suppose we draw one sample of size 100 from the population
distribution of animal pregnancy lengths.
(Round to 2 decimal places)
I. Calculate a z-score for a sample mean of 175.2.
II. Calculate a z-score for a sample mean of 152.
III. Is it more likely that we would observe a sample mean of 175.2
or 152? --- equally likely 152 175.2
Justify your answer to III in one sentence.
In: Statistics and Probability
5. Nineteen people move out of a neighborhood; four are minorities. Of the nineteen, eight move onto a block with new housing, and one of these eight is a minority. How likely is it that, if there were no discrimination, less than two people out of the eight people on this new block would be minorities? If the resulting probability is less than 0.05, evidence for discrimination exists. Does such evidence exist in this case?
6. There is an average of four accidents per year at a particular intersection. What is the probability of more than one accident there next month? Hint: Use 1 month = 1/12 of a year to first get the number of accidents that are expected next month.
Please Help I cant figure this out !!!
In: Statistics and Probability
A simple random sample of 50 items from a population with
σ = 8
resulted in a sample mean of 38. (Round your answers to two decimal places.)
(a)
Provide a 90% confidence interval for the population mean.
to
(b)
Provide a 95% confidence interval for the population mean.
to
(c)
Provide a 99% confidence interval for the population mean.
to
In: Statistics and Probability
I just need question three answered. Here is the answer to question 2 and 1 if you need it. https://www.chegg.com/homework-help/questions-and-answers/need-question-2-answered-paste-link-answer-number-one-answered-another-chegg-tutor-https-w-q46591079?trackid=UL8zNe1z
Suppose that two teams (for fun, let’s call them the Domestic Shorthairs and Cache Cows) play a series of games to determine a winner. In a best-of-three series, the games end as soon as one team has won two games. In a best-of-five series, the games end as soon as one team has won three games, and so on. Assume that the Domestic Shorthair’s probability of winning any one game is p, where .5 < p < 1. (Notice that this means that the Domestic Shorthairs are the better team.) Also assume that the outcomes are independent from game to game.
We will compare different series configurations/rules on two criteria: the probability that the better team wins the series, and the expected value of the number of games needed to complete the series.
Best-of-Three Series
Determine (exactly) the probability that the Domestic Shorthairs win a best-of-three series, as a function of p. (Show your work. Also note that you solved this for a particular value of p in Quiz 4, so you might want to review that quiz.)
Graph this function for values of .5 < p < 1 (include good axis labels), and comment on its behavior. [Hint: As with Investigation 2, you could use Excel or RStudio or Wolfram Alpha to produce the graph.]
3.Let the random variable X3 = number of games played in a
best-of-three series. Determine the probability distribution (pmf)
of X3, as a function of p. (Show your work.)
In: Statistics and Probability
Suppose hard drive A has a lifetime that is exponentially distributed with mean of 6 years and hard drive B has a lifetime that is exponentially distributed with a mean of 2 years. What is the probability that drive B lasts at least 3 times longer than drive A?
In: Statistics and Probability
The unemployment rate (UR) for PEI by quarter was as follows:
UR T (Time)
Year Quarter Rate For Regression
2018 Q1 11.9 1
Q2 7.0 2
Q3 8.1 3
Q4 10.1 4
2019 Q1 12.1 5
Q2 6.8 6
Q3 7.0 7
Q4 9.8 8
Sketch this data on a graph. Is there seasonality in the data?
Use a four quarter moving average to determine the seasonal factors for the four quarters.
Calculate the four quarter moving average;
Centre the data if necessary;
Calculate the seasonal factors for each Quarter.
Calculate the average seasonal factors for each quarter.
What percentage is the rounding error in this calculation?
In: Statistics and Probability
Research into the relationship between hours of study and grades shows widely different conclusions. A recent survey of graduates who wrote the Graduate Management Admissions Test (GMAT) had the following results.
Hours
Studied Average
(Midpoint) Score
40 210
50 300
65 345
75 455
85 540
105 660
95 700
Run the regression analysis in Excel on this data. Include your output with your answer. (Note: You may calculate by hand if you prefer).
What is the regression equation for this relationship?
Use the regression equation to predict the average score for each category of hours studied.
Plot the original data and the regression line on a scattergram. (You may use Excel).
How accurate is this regression at predicting GMAT scores based on hours studied? Explain.
Use the t statistic to determine whether the Correlation Coefficient is “significant” at the 95% confidence level.
In: Statistics and Probability