Urban traffic congestion throughout the world has been increasing in recent years, especially in developing countries. The accompanying table shows the number of minutes that randomly selected drivers spend stuck in traffic in various cities on both weekdays and weekends. Complete parts a through e below.
City_A | City_B | City_C | City_D | |
Weekday | 90 | 42 | 55 | 54 |
79 | 110 | 78 | 68 | |
132 | 62 | 78 | 42 | |
72 | 77 | 96 | 48 | |
97 | 95 | 122 | 53 | |
Weekend | 79 | 83 | 33 | 34 |
91 | 24 | 85 | 44 | |
71 | 106 | 74 | 47 | |
72 | 76 | 62 | 43 | |
63 | 79 | 36 | 43 |
a) Using alpha = 0.05, is there significant interaction between the city and time of the week?
Identify the hypotheses for the interaction between the city and time of the week. Choose the correct answer below.
A. H0: City and time of the week do not interact, H1: City and time of the week do interact
B. H0: μCity ≠ μTime, H1: City=μTime
C. H0: μCity=μTime, H1: μCity≠μTime
D. H0: City and time of the week do interact, H1: City and time of the week do not interact
Find the p-value for the interaction between city and time of the week.
p-value=????
(Round to three decimal places as needed.)
Draw the appropriate conclusion for the interaction between the city and time of the week. Choose the correct answer below.
A. Do not reject the null hypothesis. There is insufficient evidence to conclude that the city and time of the week interact.
B. Do not reject the null hypothesis. There is insufficient evidence to conclude that the means differ.
C. Reject the null hypothesis. There is insufficient evidence to conclude that the means differ.
D. Reject the null hypothesis. There is sufficientevidence to conclude that the city and time of the week interact.
b) Using two-way ANOVA and α=0.05,does the city have an effect on the amount of time stuck in traffic?
Identify the hypotheses to test for the effect of the city. Choose the correct answer below.
A. H0: μCity A=μCity B=μCity C=μCity D, H1: Not all city means are equal
B. H0: μCity=μTime, H1: μCity≠μTime
C. H0: μCity A≠μCity B≠μCity C≠μCity D, H1: μCity A=μCity B=μCity C=μCity D
D. H0: μCity A=μCity B=μCity C=μCity D, H1: μCity A>μCity B>μCity C>μCity D
Find the p-value for the effect of the city.
p-value=???
(Round to three decimal places as needed.)
Draw the appropriate conclusion for the effect of the city. Choose the correct answer below.
A. Reject the null hypothesis. There is sufficient evidence to conclude that not all city means are equal.
B. Do not rejectthe null hypothesis. There is sufficient evidence to conclude that the means differ.
C. Do not rejectthe null hypothesis. There is insufficient evidence to conclude that not all city means are equal.
D. It is inappropriate to analyze because the city and the time of the week interact.
c) Using two-way ANOVA and α=0.05, does the time of the week have an effect on the amount of time stuck in traffic?
Identify the hypotheses to test for the effect of the time of the week. Choose the correct answer below.
A.H0: μWeekday=μWeekend, H1: Not all time of the week means are equal
B. H0: μCity=μTime, H1:μCity≠μTime
C. H0: μCity A=μCity B=μCity C=μCity D, H1: Not all time of the week means are equal
D. H0: μWeekday≠μWeekend, H1:μWeekday=μWeekend
Find the p-value for the effect of the time of the week.
p-value=???
(Round to three decimal places as needed.)
Draw the appropriate conclusion for the effect of the time of the week. Choose the correct answer below.
A. Do not reject the null hypothesis. There is insufficient evidence to conclude that not all time of the week means are equal.
B. Do not reject the null hypothesis. There is sufficient evidence to conclude that the means differ.
C. Reject the null hypothesis. There is sufficient evidence to conclude that not all time of the week means are equal.
D. It is inappropriate to analyze because the city and the time of the week interact.
d) Are the means for weekdays and weekends significantly different?
A. Yes,because there is insufficient evidence to conclude that not all time of the week means are equal.
B. No, because there is insufficient evidence to conclude that not all time of the week means are equal.
C.Yes, because there is sufficient evidence to conclude that not all time of the week means are equal.
D. The comparison is unwarranted because the city and the time of the week interact.
In: Statistics and Probability
4. The university is interested in determining if the proportion of graduates obtaining a first-class degree has changed from 2016 to 2017. Out of 2800 graduates in 2016, 560 obtained a first class degree. In 2017, 805 graduates out of 3500 obtained a first class degree.
(a) Write down the method of moments estimates for the
proportion of first-class degrees
in 2016 and 2017, pˆ2016 and pˆ2017.
(b) Write down appropriate null and alternative hypotheses for this test.
(c) What assumptions are required to conduct your hypothesis test from (b), does this data satisfy them?
(d) Calculate a 90% confidence interval for the difference in the proportion of first-class degrees awarded.
(e) Using your answer to part (d), or otherwise, test your hypothesis from (b) at the 10% level. You should clearly state the conclusion of your test.
In: Statistics and Probability
asnwer the following questions
Assume you get the following M&M’s in your bag:
Blue |
Orange |
Green |
Yellow |
Red |
Brown |
Total |
10 |
14 |
15 |
9 |
2 |
6 |
56 |
Now assume that your group of 4 students had the following numbers combined:
Blue |
Orange |
Green |
Yellow |
Red |
Brown |
Total |
40 |
47 |
24 |
24 |
24 |
15 |
174 |
1- Pick one of the colors. For this color, you need to calculate 2 confidence intervals.
a.Calculate a 95% confidence interval for the proportion of the color you were assigned of M&M’s based on the count in just your bag.
b.Now with your group calculate a 95% confidence interval for the proportion of the color you were assigned of M&M’s based on the count from the class
2-Compare these two confidence intervals. What do you notice about the p-hat for each and the margin of error for each? Why do you think this is true?
Now assume the classes’ distribution is as follows:
Blue |
Orange |
Green |
Yellow |
Red |
Brown |
Total |
297 |
298 |
159 |
175 |
163 |
120 |
1212 |
3-Now calculate a 95% confidence interval for your color based on these numbers.
4-How does this interval compare with your other intervals?
The following is the distribution of colors for milk chocolate m&m’s from the company:
24% blue, 20% orange, 16% green, 14% yellow, 13% red, 13% brown.
5-Do your intervals capture the true percentage based on the above information from M&M Mars? Do all of them, or just some of them?
6-If they don’t capture the true proportion, why do you think that is?
In: Statistics and Probability
a) An article reported that, in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and 177 of these passed the probe. Assuming a stable process, calculate a 95% (two-sided) confidence interval for the proportion of all dies that pass the probe. (Round your answers to three decimal places.)
In: Statistics and Probability
2. The lifetime of light bulb is normally distributed with mean of 1400 hours and standard deviation of 200 hours.
a. What is the probability that a randomly chosen light bulb will last for more than 1800 hours?
b. What percentage of bulbs last between 1350 and 1550 hours?
c. What percentage of bulbs last less than 1.5 standard deviations below the mean lifetime or longer than 1.5 standard deviations above the mean?
d. Find a value k such that 20% of the bulbs last longer than k hours.
In: Statistics and Probability
A researcher claimed that less than 20% of adults smoke
cigarettes. A Gallup survey of 1016
randomly selected adults showed that 17% of the respondents smoke.
Is this evidence to support the
researcher’s claim?
(a) What is the sample proportion, ˆp, for this problem?
(b) State the null and alternative hypothesis.
H0 : p =
H1 : p <
Note that you should have written the same number in the null and
alternative hypotheses.
This is the value that the researcher is claiming. The sample
proportion should never go in the
null or alternative hypotheses. Therefore,the number you have in
(a) should not be in the null
or alternative hypothesis.
(c) Calculate the test statistic using the following formula:
z =
pˆ− p
√pq
n
=
where p is the value you stated in the null hypothesis and q is 1 − p.
(d) Now, using either your calculator or the normal distribution
table, look up the area that cor-
responds to the z-score you calculated in (c). You don’t need to
subtract from 1 because the
alternative hypothesis has < in it. This value is called the
p-value.
p-value=
The p-value represents the probability of getting a ˆp of .17 or
smaller if the null hypothesis
is true (p=.20). Therefore, if this probability is small then we
would doubt that the null hy-
pothesis is true (i.e. if it is not very likely to get ˆp if the
true proportion is 20% then this
gives us reason to doubt that p = .2). Thus, small p-values
support the alternative hypothesis.
P-values less than .10 or .05 are generally considered small.
(e) Circle the correct answer:
i. The p-value was small which gives us evidence that the actual
percent of adults who smoke
is less than 20%.
ii. The p-value was large so we do not have evidence that the
actual percent of adults who
smoke is less than 20%.
The answer your circled in (e) is the conclusion to the
hypothesis test. We always state conclusions in
context of the problem and we state whether we did or did not have
evidence for the alternative hypothesis.
In this case, we did have evidence for the alternative hypothesis
that the percentage of adult smokers is
less than 20%.
In: Statistics and Probability
1. Let z be a normal random variable with mean 0 and standard deviation 1. What is P(-2.25 < z < -1.1)?
0.1235 |
||
0.3643 |
||
0.8643 |
||
0.4878 |
You are offered an investment opportunity. Its outcomes and probabilities are presented in the following table.
x | P(x) |
-$1,000 | .40 |
$0 | .20 |
+$1,000 | .40 |
2. The mean of this distribution is _____________.
$400 |
||
$0 |
||
$-400 |
||
$200 |
3. T/F. The probability that the complement of an event will occur is given by P(E') = 1 - P(E)
True
False
4.
A recent survey of local cell phone retailers showed that of all cell phones sold five years ago, 64% had a camera, 28% had a music player, and 22% had both. The probability that a cell phone sold five years ago did not have either a camera or a music player is
.92 |
||
.18 |
||
.70 |
||
.30 |
5.
The sample standard deviation is related to the sample variance through what functional form?
Square root |
||
Linear |
||
Exponential |
||
Logarithm |
6.
A large industrial firm allows a discount on any invoice that is paid within 30 days. Of all invoices, 10% receive the discount. In a company audit, 10 invoices are sampled at random. The binomial probability that fewer than 3 of the 10 sampled invoices receive the discount is approximately_______________.
0.9298 |
||
0.0571 |
||
0.3486 |
||
0.1937 |
7.
Suppose x is a normal random variable with mean 60 and standard deviation 2. A z score was calculated for a number, and the z score is 3.4. What is the inverse normal calculation of x?
56.6 |
||
66.8 |
||
68.6 |
||
63.4 |
In: Statistics and Probability
Var1 | Var2 | Confidence Level | 95% | |||
113 | 141 | |||||
125 | 137 | RESULTS | ||||
134 | 126 | Group 1 | Group 2 | |||
120 | 121 | n | ||||
132 | 116 | Mean | ||||
120 | 154 | Std Dev | ||||
121 | 160 | SE | ||||
119 | 155 | t | ||||
Sp | ||||||
Margin of Error | ||||||
Point Estimate | ||||||
Lower Limit | ||||||
Upper Limit | ||||||
In: Statistics and Probability
A coin was flipped 72 times and came up heads 44 times. At the .10 level of significance, is the coin biased toward heads? (a-2) Calculate the Test statistic. (Carry out all intermediate calculations to at least four decimal places. Round your answer to 3 decimal places.) Test statistic
In: Statistics and Probability
In: Statistics and Probability
Consider the following hypotheses:
H0: μ = 38
HA: μ ≠ 38
Find the p-value for this test based on the following sample information.
a. x¯x¯ = 33; s = 11.9; n = 38
p-value < 0.01
b. x¯x¯ = 43; s = 11.9; n = 38
p-value < 0.01
c. x¯x¯ = 35; s = 11.1; n = 39
p-value < 0.01
d. x¯x¯ = 35; s = 11.1; n = 48
p-value < 0.01
In: Statistics and Probability
4) An ANOVA model with 4 groups and 10 subjects in each group has a total SS equal to 400, and within SS equal to 300, The MS between and the F value are equal to?
A. 8.57, 11.66
B. 11/66, 30.00
5) For an ANOVA model with 3 groups and total of 27 subjects, the critical value for rejecting the null hypothesis at the 0.05 level of significance is.
A. 99.50
B. 3.40
In: Statistics and Probability
. Definitions: (do not have to turn in)a. Datab. Statisticsc. Populationd. Samplee. Voluntary response samplef. Parameterg. Statistich. Quantitative datai. Qualitative dataj. Discrete datak. Continuous datal. Nominal level of measurementm. Ordinal level of measurementn. Interval level of measuremento. Ratio level of measurementp. Simple random sampleq. Systematic samplingr. Convenience samplings. Stratified samplingt. Cluster sampling
In: Statistics and Probability
Let's assume our class represents a normal population with a known mean of 90 and population standard deviation 2. There are 100 students in the class.
a. Construct the 95% confidence interval for the population mean.
b. Interpret what this means.
c. A few students have come in. Now we cannot assume normality and we don't know the population standard deviation. Let the sample mean = 90 and sample standard deviation = 3. Let's make the sample size 20. We can assume alpha to be .05. Construct the 95% confidence interval assuming this new information.
In: Statistics and Probability
A) The amount of tea leaves in a can from a particular production line is normally distributed with μ = 110 grams and σ = 25 grams. What is the probability that a randomly selected can will contain between 82 and 100 grams of tea leaves?
B) A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 450 seconds and a standard deviation of 60 seconds. The fitness association wants to recognize the boys whose times are among the top (or fastest) 10% with certificates of recognition. What time would the boys need to beat in order to earn a certificate of recognition from the fitness association? Round to one decimal place.
In: Statistics and Probability