Finish times (to the nearest hour) for 59 dogsled teams are shown below. Draw a ogive. Use five classes. 261 275 236 244 280 296 284 296 290 290 250 256 338 360 341 333 261 266 287 296 313 311 308 308 299 303 277 283 304 305 288 290 288 289 297 299 332 330 309 327 308 327 285 291 295 298 306 315 310 318 318 320 333 321 323 324 327 302 319 Select one:

Use the sample information x¯x¯ = 40, σ = 7, n = 13 to calculate the following confidence intervals for μ assuming the sample is from a normal population.

(a) 90 percent confidence. (Round your answers to 4 decimal places.)
  
The 90% confidence interval is from _____ to _____

(b) 95 percent confidence. (Round your answers to 4 decimal places.)
  
The 95% confidence interval is from _____ to _____

(c) 99 percent confidence. (Round your answers to 4 decimal places.)
  
The 99% confidence interval is from _____ to  _____

(d) Describe how the intervals change as you increase the confidence level.
  

• The interval gets narrower as the confidence level increases.

• The interval gets wider as the confidence level decreases.

• The interval gets wider as the confidence level increases.

• The interval stays the same as the confidence level increases.

A business journal investigation of the performance and timing of corporate acquisitions discovered that in a random sample of 2 ,767 ​firms, 705 announced one or more acquisitions during the year 2000. Does the sample provide sufficient evidence to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is less than 27​%?

Use α=0.10 to make your decision. What are the hypotheses for this​ test?

A. H0​: p<0.27

Ha​: p=0.27

B. H0​: p≠0.27

Ha​: p=0.27

C. H0: p=0.27

Ha: p<0.27

D. H0​: p=0.27

Ha​: p>0.27

E. H0​: p>0.27

Ha​: ≤0.27

F. H0​: p=0.27

Ha​: p≠0.27

What is the rejection​ region? Select the correct choice below and fill in the answer​ box(es) to complete your choice.

​(Round to two decimal places as​ needed.)

A. z<_________ orz>_________

B. z<___________

C.z>___________

Calculate the value of the​ z-statistic for this test.

z=_________ (Round to two decimal places as​ needed.)

What is the conclusion of the​ test?

▼

Reject

Do not reject

the null hypothesis because the test statistic

▼

is

is not

in the rejection region.​Therefore, there is

▼

insufficient

sufficient

evidence at the 0.10

level of significance to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is less than 27​%.

A machine is used to fill containers with a liquid product. Fill volume can be assumed to be normally distributed. A random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.

(d) Predict with 95% confidence the value of the 11th filled container.

(e) Predict with 95% confidence the interval containing 90% of the filled containers from the process.

Dataset ex0315 is available here.
The National Survey on Drug Use and Health, conducted in 2002 and 2003 by the Office of Applied Studies, led to the following state estimates of the total number of people (ages 12 and older) who had smoked within the last month). Fill in the following stem-and-leaf table using hundreds (of thousands) as the stems and truncating the leaves to the tens (of thousands) digit. (Enter solutions from smallest to largest. Separate the numbers with spaces.)

1. What are the differences between an event, and a simple event?
2. In your opinion, using the information that you have learned in this chapter, which of the following offer the strongest evidence for the likelihood of an event? Classical, empirical, or subjective probability...
3. Explain your understanding of Independent and Dependent events - give examples of conditional logic to help your fellow students understand these concepts in a more practical way.

Construct a frequency polygon for the following:
60-69   12
70-79   15

80-89    10

90-99      2

100-109 1

110-119   0

120-129   1

1) Present the analysis of variance (ANOVA) table in standard format.

2) Report the result of the test, including an appropriate critical value for the test.

3) Comment on the validity of test result from question

4) Append a relevant boxplot and a means plot. Use these plots to interpret the results in (2) and (3).

The data set:

"Group" "Y"
"A" -2.379
"A" 0.879
"A" -4.805
"A" -4.879
"A" -6.177
"A" 3.568
"A" -0.181
"A" 1.438
"A" -3.016
"A" -2.304
"B" 1.226
"B" 0.281
"B" 4.517
"B" 0.064
"B" 2.78
"B" 0.765
"C" 1.045
"C" -3.7
"C" -1.904
"C" -3.814
"C" -2.77
"C" 0.022
"C" -5.203
"C" -1.521
"D" -2.704
"D" 0.616
"D" -4.831
"D" 1.292
"D" -2.937
"D" -1.766
"D" -0.49
"D" 6.499
"D" -11.003
"D" -8.869
"D" -2.268
"E" -7.252
"E" -3.603
"E" -4.424
"E" -7.569
"E" -13.572
"E" 2.913
"E" 4.061
"F" 2.771
"F" 0.912
"F" 7.875
"F" 8.463
"F" 5.563
"F" 6.285
"F" 6.816

For this assignment, your group will utilize the preliminary data collected in the Topic 2 assignment. Considering the specific requirements of your scenario, complete the following steps using Excel. The accuracy of formulas and calculations will be assessed.

1. Select the appropriate discrete probability distribution. If using a binomial distribution, use the constant probability from the collected data and assume a fixed number of events of 20. If using a Poisson distribution, use the applicable mean from the collected data.
2. Identify the following: the probability of 0 events occurring, the probability of <5 events occurring, and the probability of ≥10 events occurring.
3. Using the mean and standard deviation for the continuous data, identify the applicable values of X for the following: Identify the value of X of 20% of the data, identify the value of X for the top 10% of the data, and 95% of the data lies between two values of X.
   
   How would I Calculate and do #3 and can it be explained step by step so I can better understand ?

Describe a scenario where a researcher could use a Two-Way ANOVA to answer a research question. Fully describe the scenario and the variables involved and explain the rationale for your answer. Let's say it's a test to see if the alcohol consumption is low medium or high in rural or urban areas.

Why is that test appropriate to use?

A consumer agency is investigating the blowout pressures of Soap Stone tires. A Soap Stone tire is said to blow out when it separates from the wheel rim due to impact forces usually caused by hitting a rock or a pothole in the road. A random sample of 28 Soap Stone tires were inflated to the recommended pressure, and then forces measured in foot-pounds were applied to each tire (1 foot-pound is the force of 1 pound dropped from a height of 1 foot). The customer complaint is that some Soap Stone tires blow out under small-impact forces, while other tires seem to be well made and don't have this fault. For the 28 test tires, the sample standard deviation of blowout forces was 1356 foot-pounds.

(a) Soap Stone claims its tires will blow out at an average pressure of 20,000 foot-pounds, with a standard deviation of 1026 foot-pounds. The average blowout force is not in question, but the variability of blowout forces is in question. Using a 0.1 level of significance, test the claim that the variance of blowout pressures is more than Soap Stone claims it is.

Classify the problem as being a Chi-square test of independence or homogeneity, Chi-square goodness-of-fit, Chi-square for testing or estimating σ² or σ, F test for two variances, One-way ANOVA, or Two-way ANOVA, then perform the following.

One-way ANOVAF test for two variances     Chi-square test of independenceChi-square for testing or estimating σ² or σChi-square test of homogeneityChi-square goodness-of-fitTwo-way ANOVA

(i) Give the value of the level of significance.

State the null and alternate hypotheses.

H_o: σ² = 1052676; H₁: σ² > 1052676H_o: σ² = 1052676; H₁: σ² ≠ 1052676     H_o: σ² < 1052676; H₁: σ² = 1052676H_o: σ² = 1052676; H₁: σ² < 1052676

(ii) Find the sample test statistic. (Use two decimal places.)


(iii) Find the P-value of the sample test statistic. (Use four decimal places.)

(iv) Conclude the test.

Since the P-value is greater than or equal to the level of significance α = 0.10, we fail to reject the null hypothesis.Since the P-value is less than the level of significance α = 0.10, we reject the null hypothesis.     Since the P-value is less than the level of significance α = 0.10, we fail to reject the null hypothesis.Since the P-value is greater than or equal to the level of significance α = 0.10, we reject the null hypothesis.

(v) Interpret the conclusion in the context of the application.

At the 10% level of significance, there is insufficient evidence to conclude that the variance is not greater than claimed.At the 10% level of significance, there is sufficient evidence to conclude that the variance is greater than claimed.     At the 10% level of significance, there is sufficient evidence to conclude that the variance is not greater than claimed.At the 10% level of significance, there is sufficient evidence to conclude that the variance is greater than claimed.

(b) Find a 90% confidence interval for the variance of blowout pressures, using the information from the random sample. (Use one decimal place.)
< σ² <  square foot-pounds

You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05.

      Ho:μ=86.1Ho:μ=86.1
      Ha:μ≠86.1Ha:μ≠86.1

You believe the population is normally distributed and you know the standard deviation is σ=14.2σ=14.2. You obtain a sample mean of M=84.5M=84.5 for a sample of size n=63n=63.

What is the critical value for this test? (Report answer accurate to three decimal places.)
critical value = ±±

What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =

The test statistic is...

• in the critical region
• not in the critical region

This test statistic leads to a decision to...

• reject the null
• accept the null
• fail to reject the null

As such, the final conclusion is that...

• There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 86.1.
• There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 86.1.
• The sample data support the claim that the population mean is not equal to 86.1.
• There is not sufficient sample evidence to support the claim that the population mean is not equal to 86.1.

When might one be interested in the mode or the median rather that the average? When might one be interested in the range rather than the standard deviation?

The data in the table is the number of absences for 7 7 students and their corresponding grade. Number of Absences 4 4 4 4 6 6 6 6 6 6 6 6 7 7 Grade 3.7 3.7 3.3 3.3 3.3 3.3 3 3 2.5 2.5 1.9 1.9 1.5 1.5 Table Copy Data Step 1 of 5: Calculate the sum of squared errors (SSE). Use the values b 0 =5.8278 b0=5.8278 and b 1 =−0.5537 b1=−0.5537 for the calculations. Round your answer to three decimal places. Step 2 of 5: Calculate the estimated variance of errors, s 2 e se2 . Round your answer to three decimal places. Calculate the estimated variance of slope, s 2 b 1 sb12 . Round your answer to three decimal places. Construct the 95% 95% confidence interval for the slope. Round your answers to three decimal places. Step 5 of 5: Construct the 98% 98% confidence interval for the slope. Round your answers to three decimal places.

The five most common words appearing in spam emails are shipping!, today!, here!, available, and fingertips!. Many spam filters separate spam from ham (email not considered to be spam) through application of Bayes' theorem. Suppose that for one email account, in every messages is spam and the proportions of spam messages that have the five most common words in spam email are given below.

shipping!        0.050      

today!             0.047

here!              0.034

Available       0.016

fingertips!      0.016

Also suppose that the proportions of ham messages that have these words are

Round your answers to three decimal places.

If a message includes the word shipping!, what is the probability the message is spam?

If a message includes the word shipping!, what is the probability the message is ham?

Should messages that include the word shipping! be flagged as spam?

b. If a message includes the word today!, what is the probability the message is spam?

If a message includes the word here!, what is the probability the message is spam?

Which of these two words is a stronger indicator that a message is spam?

Why?

Because the probability is

c. If a message includes the word available, what is the probability the message is spam?

If a message includes the word fingertips!, what is the probability the message is spam?

Which of these two words is a stronger indicator that a message is spam?

Why?

Because the probability is

d. What insights do the results of parts (b) and (c) yield about what enables a spam filter that uses Bayes' theorem to work effectively?

Explain.

It is easier to distinguish spam from ham when a word occurs in spam and less often in ham.