Suppose we have a 20% chance of winning a game and play 30 times. What is...

Suppose we have a 20% chance of winning a game and play 30 times. What is the probability we win the game 4-13 times (note: 4 and 13 are included in the interval)? Show your work. If you use a calculator, you must identify the list(s) and/or function(s), with input(s), you used. Give your answer to three decimal places.

Expert Solution

Here we see that n=30 is constant, p=0.20 is same for all, events are independent and only two outcomes

Hence binomial distribution is satisfied

x	P(x)=BINOMDIST(x,n,p,0)
0	0.0012
1	0.0093
2	0.0337
3	0.0785
4	0.1325
5	0.1723
6	0.1795
7	0.1538
8	0.1106
9	0.0676
10	0.0355
11	0.0161
12	0.0064
13	0.0022
14	0.0007
15	0.0002
16	0.0000
17	0.0000
18	0.0000
19	0.0000
20	0.0000
21	0.0000
22	0.0000
23	0.0000
24	0.0000
25	0.0000
26	0.0000
27	0.0000
28	0.0000
29	0.0000
30	0.0000

So

Using the binomial distribution table we get

orchestra answered 3 years ago

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