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Ammonia, NH3, and oxygen can be reacted together in the presence of a catalyst to form...

Ammonia, NH3, and oxygen can be reacted together in the presence of a catalyst to form only nitrogen monoxide and water. The number of moles of oxygen consumed for every 9.00 moles of NO produced is :

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Expert Solution

4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)

From the above balanced equation it is clear that 4 moles of NO is formed from 5 moles O2 consumption.

Therefore for the production of 9.00 moles of NO, moles of O2 consumed = (5 x 9.00)/4

                                                                                                                     = 11.25 mol

queen_honey_blossom answered 1 year ago
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