In: Statistics and Probability
You are in an Intro Psych class of 137 students. You ask 25 of your classmates their age and calculate a mean of 18.2 and a sample standard deviation of 1.5. Calculate the standard error and report the 80% and 99% confidence intervals for the estimated average age of the class.
Solution:
The standard error is given as follows:
Where, SE is standard error, s is sample standard deviation and n is sample size.
We have, s = 1.5 and n = 25
The standard error is 0.3.
The 80% confidence interval estimate of population mean is given as follows:
Where, x̄ is sample mean, s is sample standard deviation, n is sample size and t(0.20/2, n-1) is critical t-value to construct 80% confidence interval.
We have, x̄ = 18.2, s = 1.5 and n = 25
Using t-table we get, t(0.20/2, 25-1) = 1.318
Hence, 80% confidence intervals for the estimated average age of the class is,
The 80% confidence interval for the estimated average age of the class is (17.8046, 18.5954).
The 99% confidence interval estimate of population mean is given as follows:
Where, x̄ is sample mean, s is sample standard deviation, n is sample size and t(0.01/2, n-1) is critical t-value to construct 99% confidence interval.
We have, x̄ = 18.2, s = 1.5 and n = 25
Using t-table we get, t(0.01/2, 25-1) = 2.797
Hence, 99% confidence intervals for the estimated average age of the class is,
The 99% confidence interval for the estimated average age of the class is (17.3609, 19.0391).
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