In: Finance
Edelman Engineering is considering including two pieces of equipment, a truck and an overhead pulley system in this year’s capital budget. The projects are independent. The cash outlay for the truck is $17,100 and for the pulley system it is $22,430. The firm’s cost of capital is 14%. After tax cash flows are as follows:
Year Truck Pulley
1 $5,100 $7,500
2 $5,100 $7,500 3 $5,100 $7,500 4 $5,100 $7,500
5 $5,100 $7,500
Calculate the PB, DPB in excel for each project. Indicate the correct accept or reject decision for each project.
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computation of payback period : Payback period is period were initial investment is recovered by cash flow. | ||||||||||||
cumulative cash flow | ||||||||||||
year | Truck | Pulley | Truck | Pulley | ||||||||
0 | -17100 | -22430 | -17100 | -22430 | ||||||||
1 | 5100 | 7500 | -12000 | -14930 | ||||||||
2 | 5100 | 7500 | -6900 | -7430 | ||||||||
3 | 5100 | 7500 | -1800 | 70 | ||||||||
4 | 5100 | 7500 | 3300 | 7570 | ||||||||
5 | 5100 | 7500 | 8400 | 15070 | ||||||||
Payback period Truck = | =3+1800/5100 | 3.35 | year | |||||||||
Payback period pulley = | =2+7430/7500 | 2.99 | year | |||||||||
Decision: Since Pulley has lower payback period therefore Pully should be accepted over Truck | ||||||||||||
computation of discounted payback period : discounted payback period is period were initial investment is recovered at discounted cash flow level. | ||||||||||||
i | ii | iii | iv=i*iii | v=ii*iii | vi | vii | ||||||
Discounted cash flow | cumulative discounted cash flow | |||||||||||
year | Truck | Pulley | PVIF @ 14% | Truck | Pulley | Truck | Pulley | |||||
0 | -17100 | -22430 | 1.0000 | (17,100) | (22,430) | (17,100) | (22,430) | |||||
1 | 5100 | 7500 | 0.8772 | 4,474 | 6,579 | (12,626) | (15,851) | |||||
2 | 5100 | 7500 | 0.7695 | 3,924 | 5,771 | (8,702) | (10,080) | |||||
3 | 5100 | 7500 | 0.6750 | 3,442 | 5,062 | (5,260) | (5,018) | |||||
4 | 5100 | 7500 | 0.5921 | 3,020 | 4,441 | (2,240) | (577) | |||||
5 | 5100 | 7500 | 0.5194 | 2,649 | 3,895 | 409 | 3,318 | |||||
Payback period Truck = | =4+2240/2649 | 4.85 | year | |||||||||
Payback period pulley = | =4+577/3895 | 4.15 | year | |||||||||
Decision: Since Pulley has lower discounted payback period therefore Pully should be accepted over Truck | ||||||||||||