Question

In: Statistics and Probability

In a survey of 700 community college students, 481 indicated that they have read a book...

  1. In a survey of 700 community college students, 481 indicated that they have read a book for personal enjoyment during the school year (based on data from the Community College Survey of Student Engagement).
    1. Determine a 90% confidence interval for the proportion of community college students who have read a book for personal enjoyment during the school year. You must show your work. Round the limits to the nearest thousandth.
    1. For a 90% confidence interval, would it be unusual if less than 450 students indicated that they have read a book for personal enjoyment during the school year? Justify your answer.
    1. For a 99% confidence interval, would it be unusual if less than 450 students indicated that they have read a book for personal enjoyment during the school year? Justify your answer.

Solutions

Expert Solution

Here,   = 481/700 = 0.6871

a) In general, (1-)% confidence interval for the population proportion is obtained as follows :

where Z (/2) = Z (0.05) = 1.6449

Thus, 90% confidence interval for the population proportion is:

( 0.6583 , 0.7159 )
( 460.81, 501.149 ) (Here n = 700 is multiplied to the above 90% CI )

b) Since the 90% confidence interval for the population proportion does not contains values less than 450, it would be unusual if less than 450 students indicated that they have read a book for personal enjoyment during the school year.

c) 99%  confidence interval for the population proportion is:

( 0.6420, 0.7322 )
( 449.400, 512.540 ) (Here n = 700 is multiplied to the above 90% CI )
Since the 99% confidence interval for the population proportion does contains values less than 450, it would not be unusual if less than 450 students indicated that they have read a book for personal enjoyment during the school year.

Hope this answers your query!


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