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In: Chemistry

Determine the pH (to two decimal places) of the solution that is produced by mixing 552...

Determine the pH (to two decimal places) of the solution that is produced by mixing 552 mL of 7.68×10-3 M HCl with 60.3 mL of 1.80×10-3 M KH.​

Solutions

Expert Solution

millimoles of HCl = 552 x 7.68 x 10^-3 = 4.24

millimoles of KH = 60.3 x 1.80 x 10^-3 = 0.108

H+   +    H-     ----------------> H2
4.24   0.108                           0

4.13      0                         0.108

[H+] left = 4.13 / (552 + 60.3)

              = 6.475 x 10^-3 M

pH = -log [H+]

pH = 2.17


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