Determine the pH (to two decimal places) of the solution that is produced by mixing 552...

Determine the pH (to two decimal places) of the solution that is produced by mixing 552 mL of 7.68×10^-3 M HCl with 60.3 mL of 1.80×10^-3 M KH.

Expert Solution

millimoles of HCl = 552 x 7.68 x 10^-3 = 4.24

millimoles of KH = 60.3 x 1.80 x 10^-3 = 0.108

H+ + H- ----------------> H2
4.24 0.108 0

4.13 0 0.108

[H+] left = 4.13 / (552 + 60.3)

= 6.475 x 10^-3 M

pH = -log [H+]

pH = 2.17

queen_honey_blossom answered 2 years ago

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