In: Statistics and Probability
assume that women's heights are normally distributed with a mean 64.6 in. and a standard deviation 2.6 in. if 49 women are randomly selected, find the probability they have a mean less than 65 in
Solution :
Given that ,
mean = = 64.6
standard deviation = = 2.6
n = 49
= 64.6
= / n = 2.6 / 49
P( < 65) = P(( - ) / < (65 - 64.6) / 2.6 / 49)
= P(z < 1.08)
= 0.8599