In: Statistics and Probability
assume that women's heights are normally distributed with a mean 64.6 in. and a standard deviation 2.6 in. if 49 women are randomly selected, find the probability they have a mean less than 65 in
Solution :
Given that ,
mean =
= 64.6
standard deviation =
= 2.6
n = 49
= 64.6
=
/
n = 2.6 /
49
P(
< 65) = P((
-
) /
< (65 - 64.6) / 2.6 /
49)
= P(z < 1.08)
= 0.8599