The reaction, 2A + 2B → C + D, has a rate constant of 6.0 ×...

The reaction, 2A + 2B → C + D, has a rate constant of 6.0 × 10-3 M-2 s-1 at 0°C. From this information, can we determine the order of this rate law? If so what is the order?

Expert Solution

queen_honey_blossom answered 2 years ago

Using the data, determine the rate constant of this reaction. A+2B ---> C+D

Using the data, determine the rate constant of this reaction.A+2B ---> C+Dtrial [A] (M) [B] (M) Rate (M/s)1 0.290 0.260 0.02012 0.290 0.520 0.02013 0.580 0.260 0.0804Number K=???Units= ?? M.s-1, M-2s-1, s-1,M-1s-1

The rate constant for the reaction: 2A -> 2B + C is 0.881M-1*s-1 at 333 degrees...

The rate constant for the reaction: 2A -> 2B + C is 0.881M-1*s-1 at 333 degrees Celcius. (a) Starting with a concentration of 0.0955 M, calculate the concentration of A after 12.5 seconds. (b) Calculate the half-live when [A] = 0.0444 M.

Using the given data, determine the rate constant of this reaction. A+2B ------> C+D Trial [A](M)...

Using the given data, determine the rate constant of this reaction. A+2B ------> C+D Trial [A](M) [B](M) Rate (M/s) 1. 0.270 0.380 0.0235 2 0.270 0.760 0.0235 3 0.540 0.380 0.0940 K=? What units should be used?

Using the given data, determine the rate constant of this reaction. A+2B---> C+D Trial (A) (B)(M)...

Using the given data, determine the rate constant of this reaction. A+2B---> C+D Trial (A) (B)(M) Rate (M/s) 1 0.380 0.330 0.0153 2 0.380 0.660 0.153 3 0.760 0.330 0.0612 k= (inculde units)

Using the given data, determine the rate constant of this reaction. A + 2B --> C...

Using the given data, determine the rate constant of this reaction. A + 2B --> C + D Given Data: Trial [A](M) [B](M) RATE (M/s) 1 .230 .330 0.0231 2 .230 .660 0.0231 3 .460 .330 0.0924 k=? the units are M-1 s-1

A general reaction written as 2A + 2B → C + 2D is studied and yields the...

A general reaction written as 2A + 2B → C + 2D is studied and yields the following data. [A]0 [B]0 Initial Δ[C]/Δt 0.100 M 0.100 M 4.00 × 10–5 mol/L • s 0.200 M 0.100 M 4.00 × 10–5 mol/L • s 0.100 M 0.200 M 8.00 × 10–5 mol/L • s For the first of the reactions in the table of data, determine –Δ[B]/Δt. A) 8.00 × 10–5 B) 1.60 × 10–4 C) 4.00 × 10–5 D) 2.00 ×...

The gas-phase, elementary reaction: 2A + 1/2B ----> C + 2D will be conducted in a...

The gas-phase, elementary reaction: 2A + 1/2B ----> C + 2D will be conducted in a constant volume, isothermal batch reactor. The reactor is initially charged with a stoichiometric ratio of A and B. The reaction is moderately exothermic and the heat of reaction will be removed via cooling water. The following data is available: Initial Conditions: Initial concentration of A = Cao, initial concentration of B = Cbo Cooling water: inlet temperature = Ta1, outlet temperature = Ta2, water...

The reaction A + 2B  C + D is taking place in a batch reactor....

The reaction A + 2B  C + D is taking place in a batch reactor. (Cao =1M, Cbo = 3M k=0.001 (1/M^2*min)). a) Assuming an elementary rate law, find the time necessary to reach the conversion of 0.9. You can assume constant volume batch reactor with well mixing. Also form the stoichiometric table. (15 points) b) Sometimes it is hard to obtain numerical solutions to the complex integrals. Find the answer using trapezoidal, Simpson 1/3 and Simpson 3/8, Five-point...

Consider the following reaction at 283 K: 2A + B → C + D where rate...

Consider the following reaction at 283 K: 2A + B → C + D where rate = k[A][B]2. An experiment was performed where [A]o = 2.67 M and [B]o = 0.00241 M. A plot of 1/[B] vs. time has a slope of 10.01. What will the rate of this reaction be when [A] = [B] = 0.345 M?

In the reaction A + 2B ---> 3C + D , If 93g of A and...

In the reaction A + 2B ---> 3C + D , If 93g of A and 85g of B are combined, which reactant is the limiting reagent, and what is the theoretical yield of C in grams? (MM(A)= 55g/mole, MM(B)= 48g/mole, MM(C)= 37g/mol)

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