Question

In: Statistics and Probability

The monthly incomes from a random sample of workers in a factory are shown below: 18,14,12,14,12...

The monthly incomes from a random sample of workers in a factory are shown below:

18,14,12,14,12

a. Compute the margin of error (in dollars) at 98% confidence

b. Compute a 98% confidence interval for the mean of the population. Assume the population has a normal distribution. Give your answer in dollars.

Solutions

Expert Solution

a)

sample mean         x= 14.000
sample size             n= 5
sample std deviation s= 2.449
std error sx=s/√n= 1.0954
for 98% CI; and 4 df, critical t= 3.7470
margin of error E=t*std error                            = 4.10

b)

lower bound=sample mean-E = 9.90
Upper bound=sample mean+E= 18.10

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