In: Statistics and Probability
The monthly incomes from a random sample of workers in a factory are shown below:
18,14,12,14,12
a. Compute the margin of error (in dollars) at 98% confidence
b. Compute a 98% confidence interval for the mean of the population. Assume the population has a normal distribution. Give your answer in dollars.

a)
| sample mean x= | 14.000 |
| sample size n= | 5 |
| sample std deviation s= | 2.449 |
| std error sx=s/√n= | 1.0954 |
| for 98% CI; and 4 df, critical t= | 3.7470 | |
| margin of error E=t*std error = | 4.10 | |
b)
| lower bound=sample mean-E = | 9.90 | |
| Upper bound=sample mean+E= | 18.10 | |