Question

please answer with coding from The second edition C programming language textbook

/* Changes all occurrences of t in s to u, result stored in v

*

* Example:

*

* char v[100];

* replace("hello", "el", "abc", v) => v becomes "habclo"

* replace("", "el", "abc", v) => v becomes "" (no change)

* replace("hello", "abc", "def", v) => v becomes "hello" (no change)

* replace("utilities", "ti", "def", v) => v becomes "udeflidefes"

*

*/

void replace(char *s, char *t, char *u, char *v)

{

}

Answer 1

void replace(char *s, char *t, char *u, char *v)
{
    int flag,len=strlen(t);
    for(int i=0;s[i]!='\0';i++)
    {
        
        if (strncmp(s+i,t,len) == 0)
        {
            strcat(v,u);
            i=i+len-1;
            continue;
        }
        strncat(v,s+i,1);
            
    }
    printf("%s\n",v); //you can omit this line if you don't need it,I did it to print the result
}

Here is the full code , if you need

#include<stdio.h>
#include<string.h>


void replace(char *s, char *t, char *u, char *v)
{
    int flag,len=strlen(t);
    for(int i=0;s[i]!='\0';i++)
    {
        
        if (strncmp(s+i,t,len) == 0)
        {
            strcat(v,u);
            i=i+len-1;
            continue;
        }
        strncat(v,s+i,1);
            
    }
    printf("%s\n",v);
}


int main()
{
    char s[]="utilities";
    char t[]="ti";
    char u[]="def";
    char v[100]={0};
    replace(s,t,u,v);
    return 0;
}