In: Biology
1. The student also took samples at different times during the growth to do dilution plating and get viable plate counts. Here are the results for the samples taken at hours 3 and 6:
3 hours | 6 hours |
10-3 dilution = too many to count | 10-5 dilution = too many to count |
10-4 dilution = 476 CFUs | 10-6 dilution = 155 CFUs |
10-5 dilution = 49 CFUs | 10-7 dilution = 17 CFUs |
10-6 dilution = 5 CFUs | 10-8 dilution = 2 CFUs |
Which dilution will give the best estimate for the 3 hour time point? Which will give the best estimate at 6 hours? Using these data, how many CFUs/ml were present in the original culture at times 3 and 6 hours? (Assume 1 ml inoculum for for each plate)
Answer:
For 3 hours, 10-5dilution gave 49 CFUs. So 10-5gave the best estimate at 3 hours.
=4.9x106CFU/ml were present in the original culture at 3 hours.
For 6 hours, 10-6 dilution gave 155 CFUs. So 10-6gave the best estimate at 6 hours.
=1.55x108 CFU/ml were present in the original culture at 6 hours.
QUESTION 2. Calculate the generation time (minutes/generation) of the student's culture using the CFUs/ml that you calculated in question 2.
2.
Viable plate count = 30 to 300 colonies
For 3 hours, best calculations can be done using 10^-5 dilution because the count is in the range of 30 to 300. Similarly, for 6 hours, we will use 10^-6 dilution.
CFU per mL = #colonies / (volume plated × dilution)
For 3 hours,
CFU per mL = 49 / (1 × 10^-5) = 49 × 10^5 = 4.9 × 10^6 CFU per mL
For 6 hours,
CFU per mL = 155 / (1 × 10^-6) = 155 × 10^6 CFU per mL
Original cell concentration = average of both the values given above = (4.9 × 10^6) + (155 × 10^6) / 2 = 79.95 × 10^6 = 7.995 × 10^7 CFU per mL
7.995 × 10^7 CFU per mL
Generation time = time taken by one generation to grow
Nt = No 2^n
155 × 10^6 = (4.9 × 10^6) 2^n
2^n = 31.63 = 32 (approx)
2^5 = 2^n
n = 5 (number of generations)
5 generations occured in 3 hours (180 minutes)
1 generation would have occured in 180/5 = 36 minutes
Generation time = 36 minutes
Please rate high.