Question

Briefly discuss the chemistry of the aqua complexes of [Mo3Q4(H2O)9] 4+ (where Q = S or Se).

Answer 1

he response of Pd dark with [Mo3Se4(H2O)9]4+ in 2 M HCl gives the single 3D shape [Mo3(PdCl)Se4(H2O)9]3+, which on expulsion of Cl− structures the edge-connected twofold 3D square [{Mo3PdSe4(H2O)9}2]8+. No comparable responses of [W3S4(H2O)9]4+ and [W3Se4(H2O)9]4+ are watched, and for no situation is Pt dark joined into the trinuclear species. The gem structure of [{Mo3PdSe4(H2O)9}2](pts)8·18H2O has been resolved (pts− = p-toluenesulfonate), and is reliable with Mo–Mo and Mo–Pd holding. Properties of the Pd subordinates of both [Mo3Q4(H2O)9]4+ (Q = S, Se) are considered. No heteroatom exchange is seen on blending [Mo3(PdCl)Se4(H2O)9]3+ with [Mo3S4 (H2O)9]4+ just like the instance of [Mo3SnSe4(H2O)12]6+ with [Mo3S4 (H2O)9]4+. The single 3D squares [Mo3(PdCl)Q4 (H2O)9]3+ (Q = S, Se), respond 1 ∶ 1 with SnCl3− to give [Mo3(PdSnCl3)Q4(H2O)9]3+ with Pd–Sn holding. Development constants K (25 °C) are 1.15 × 103 M−1 (Q = S) and 9.5 × 103 M−1 (Q = Se). On blending the heterometal 3D shapes [Mo3PdS4(H2O)10]4+ and [Mo3SnS4(H2O)12]6+ in 2 M HCl no Pd–Sn holding happens. With [Pd(H2O)4]2+ and [Mo3SnS4(H2O)12]6+ in 2.0 M HClO4, response steps Mo3SnS46+ → Mo3S44+ + SnII, trailed by SnII + PdII → SnIV + Pd0 are watched, and Pd0 is hastened. Rate constants for the oxidation of [Mo3(PdCl)S4(H2O)9]4+ and [{Mo3PdS4(H2O)9}2]8+ with [Co(dipic)2]− (dipic = 2,6-pyridinedicarboxylate) are inside a variable of 2, demonstrating no noteworthy change in redox properties. This appears differently in relation to the conduct of single and corner-shared twofold 3D squares e.g. M′ = Sn.