In: Statistics and Probability
Bardi Trucking Co., located in Cleveland, Ohio, makes deliveries in the Great Lakes region, the Southeast, and the Northeast. Jim Bardi, the president, is studying the relationship between the distance a shipment must travel and the length of time, in days, it takes the shipment to arrive at its destination. To investigate, Mr. Bardi selected a random sample of 20 shipments made last month. Shipping distance is the independent variable and shipping time is the dependent variable. The results are as follows:
Shipment | Distance (miles) | Shipping Time (days) | Shipment | Distance (miles) | Shipping Time (days) | |||
1 | 678 | 3 | 11 | 814 | 11 | |||
2 | 758 | 14 | 12 | 782 | 5 | |||
3 | 733 | 14 | 13 | 753 | 7 | |||
4 | 802 | 15 | 14 | 831 | 3 | |||
5 | 832 | 15 | 15 | 723 | 6 | |||
6 | 684 | 6 | 16 | 746 | 7 | |||
7 | 683 | 9 | 17 | 632 | 5 | |||
8 | 768 | 4 | 18 | 740 | 13 | |||
9 | 776 | 10 | 19 | 778 | 6 | |||
10 | 840 | 13 | 20 | 822 | 7 | |||
b-1. Fill in the blanks. (Round your answers to 3 decimal places. Negative values should be indicated by minus sign.)
x⎯⎯x¯ 758.75 | |
y⎯⎯y¯. 8.65 | |
Sx. 57.95 | |
Sy. 4.13 | |
r. 0.34 | |
b-2. State the decision rule for 0.10 significance level: H0: ρ ≤ 0; H1: ρ > 0. (Round your answer to 3 decimal places.)
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b-3. Compute the value of the test statistic. (Negative value should be indicated by a minus sign. Round your answer to 3 decimal places.)
Value of the test statistic1.534. selected answer correct
b-4. Can we conclude that there is a positive correlation between distance and time? Use the 0.10 significance level.
Rejectselected answer correct | H0. We | can selected answer correct | conclude that there is a positive correlation between distance and time. |
c-1. Determine the coefficient of determination. (Round your answer to 3 decimal places.)
c-2. Fill in the blank below. (Round your answer to 1 decimal place.)
Determine the standard error of estimate. (Round your answer to 3 decimal places.)
I want the answer from 1 c-1
test statistic= r*sqrt(n-2)/sqrt(1r^2)
t= 0.34*sqrt(18)/sqrt(1-0.116)
t=1.534
P value=0.0712
Since P value smaller than 0.1 reject H0. there is positive correlation.
COEFFICIENT OF DETERMINATION = r squared= (0.34)^2= 0.116 it indicates that the model explains 11.6% of the variability of the response data around its mean.
Standard error of estimate= 3.993