In: Statistics and Probability
A national survey reports that the average number of screens (TVs, computers, tablets, and smartphones) in a single-family household 11.8, with a standard deviation of 4.13. You believe that average may be different in Hartsville. You collect a sample of 35 households in Hartsville, and find that the average number of screens is 12.01.
Follow the outline to test the hypothesis at a significance level of ?=0.05:
?0:?=11.8??:?≠11.8
Identify the critical z-score for a significance level of ?=0.05
Select your answer from one of the following options.
??=2.33
??=−1.64
??=±2.33
??=1.64
??=±1.96
Which of the graphs below best represents the rejection region?
Select your answer from one of the following options.Graph A
Graph B
Graph C
Round your answer to 2 decimal places.
Using the standardized test statistic and the critical z-score, draw a conclusion and interpret your result.
Select your answer from one of the following options.Reject the null hypothesis There is not enough evidence to conclude that the average number of screens per household in Hartsville is different from the national average.
Reject the null hypothesis There is enough evidence to conclude that the average number of screens per household in Hartsville is different from the national average.
Fail to reject the null hypothesis. There is not enough evidence to conclude that the average number of screens per household in Hartsville is different from the national average.
Fail to reject the null hypothesis. There is enough evidence to conclude that the average number of screens per household in Hartsville is different from the national average.