Question

In: Statistics and Probability

A national survey reports that the average number of screens (TVs, computers, tablets, and smartphones) in...

A national survey reports that the average number of screens (TVs, computers, tablets, and smartphones) in a single-family household 11.8, with a standard deviation of 4.13. You believe that average may be different in Hartsville. You collect a sample of 35 households in Hartsville, and find that the average number of screens is 12.01.

Follow the outline to test the hypothesis at a significance level of ?=0.05:

?0:?=11.8??:?≠11.8

Identify the critical z-score for a significance level of ?=0.05

Select your answer from one of the following options.

  • a.

    ??=2.33

  • b.

    ??=−1.64

  • c.

    ??=±2.33

  • d.

    ??=1.64

  • e.

    ??=±1.96

    Which of the graphs below best represents the rejection region?

    Select your answer from one of the following options.
    • A.

      Graph A

    • B.

      Graph B

    • C.

      Graph C

    Calculate the standardized test statistic ?=?⎯⎯⎯−??/?√

    Round your answer to 2 decimal places.

    Using the standardized test statistic and the critical z-score, draw a conclusion and interpret your result.

    Select your answer from one of the following options.
    • a.

      Reject the null hypothesis There is not enough evidence to conclude that the average number of screens per household in Hartsville is different from the national average.

    • b.

      Reject the null hypothesis There is enough evidence to conclude that the average number of screens per household in Hartsville is different from the national average.

    • c.

      Fail to reject the null hypothesis. There is not enough evidence to conclude that the average number of screens per household in Hartsville is different from the national average.

    • d.

      Fail to reject the null hypothesis. There is enough evidence to conclude that the average number of screens per household in Hartsville is different from the national average.

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