Question

In: Statistics and Probability

Problem 1 (Test for the difference among multiple proportions) How common are financial cost or contractual...

Problem 1 (Test for the difference among multiple proportions)

How common are financial cost or contractual constrains associated with smartphone ownership? A survey of smartphone owners found that 48% of the 18 – to 29 –years–olds, 38% of the 30- to 49-years-olds, 25% of the 50- to 64-years-olds, and 19% of those 65 or older have reached the maximum amount of data they are allowed to use as part of their plan, at least on occasion.

Suppose the survey was based on 200 smartphone owners in each of the four age groups: 18 to 29, 30 to 49, 50 to 64, and 65 +.

  1. At the 0.05 level of significance, is there evidence of a difference among the age groups in the proportion of smartphone owners who have reached the maximum amount of data they are allowed to use as part of their plan, at least on occasion?

Problem 2 (Test for independence among proportions)

What makes sales leaders tick? Mercuri International conducted a study to explore sales strategies, processes, and support systems within businesses. Organizations were categorized by sales performance level (top performers vs. middle performers vs. bottom performers) and extent to which the organization invests in customer satisfaction. Results were organized in the following table.

Sales Performance Level

Level Of Investment

Top

Middle

Bottom

Total

Annually

53

318

44

415

Every 2-4 years

40

245

23

308

Never

11

158

34

203

Total

104

721

101

926

At the 0.05 level of significance, is there evidence of a significant relationship between sales performance level and level of investment in customer satisfaction?

Solutions

Expert Solution

1)

observed frequencey, O expected proportion expected frequency,E (O-E) (O-E)²/E
96 0.250 65.00 31.00 14.785
76 0.250 65.00 11.00 1.862
50 0.250 65.00 -15.00 3.462
38 0.250 65.00 -27.00 11.215

chi square test statistic,X² = Σ(O-E)²/E =   31.323              
                  
level of significance, α=   0.05              
Degree of freedom=k-1=   4   -   1   =   3
                  
P value =   0.0000   [ excel function: =chisq.dist.rt(test-stat,df) ]          
Decision: P value < α, Reject Ho  

There is enough evidence of     difference among the age groups in the proportion of smartphone owners who have reached the maximum amount of data they are allowed to use as part of their plan, at least on occasion   
===============

(Test for independence among proportions)

Ho: There is no significant relationship between sales performance level and level of investment in customer satisfaction

Ha: There is a  significant relationship between sales performance level and level of investment in customer satisfaction

Chi-Square Test of independence
Observed Frequencies
Level Of Investment Top Middle Bottom Total
Annually 53 318 44 415
Every 2-4 years 40 245 23 308
Never 11 158 34 203
Total 104 721 101 926
Expected frequency of a cell = sum of row*sum of column / total sum
Expected Frequencies
Top Middle Bottom Total
Annually 104*415/926=46.609 721*415/926=323.126 101*415/926=45.265 415
Every 2-4 years 104*308/926=34.592 721*308/926=239.814 101*308/926=33.594 308
Never 104*203/926=22.799 721*203/926=158.059 101*203/926=22.141 203
Total 104 721 101 926
(fo-fe)^2/fe Top Middle Bottom total
Annually 0.876 0.081 0.035 0.993
Every 2-4 years 0.846 0.112 3.341 4.299
Never 6.106 0.000 6.351 12.458

Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe =   17.749  
      
Level of Significance =   0.05  
Number of Rows =   3  
Number of Columns =   3  
Degrees of Freedom=(#row - 1)(#column -1) = (3- 1 ) * ( 3- 1 ) =   4  
      
p-Value =   0.001   [Excel function: =CHISQ.DIST.RT(χ²,df) ]
Decision:    p-value < α , Reject Ho  

there is a evidence of a significant relationship between sales performance level and level of investment in customer satisfaction


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