In: Statistics and Probability
Problem 1 (Test for the difference among multiple proportions)
How common are financial cost or contractual constrains associated with smartphone ownership? A survey of smartphone owners found that 48% of the 18 – to 29 –years–olds, 38% of the 30- to 49-years-olds, 25% of the 50- to 64-years-olds, and 19% of those 65 or older have reached the maximum amount of data they are allowed to use as part of their plan, at least on occasion.
Suppose the survey was based on 200 smartphone owners in each of the four age groups: 18 to 29, 30 to 49, 50 to 64, and 65 +.
Problem 2 (Test for independence among proportions)
What makes sales leaders tick? Mercuri International conducted a study to explore sales strategies, processes, and support systems within businesses. Organizations were categorized by sales performance level (top performers vs. middle performers vs. bottom performers) and extent to which the organization invests in customer satisfaction. Results were organized in the following table.
Sales Performance Level |
||||
Level Of Investment |
Top |
Middle |
Bottom |
Total |
Annually |
53 |
318 |
44 |
415 |
Every 2-4 years |
40 |
245 |
23 |
308 |
Never |
11 |
158 |
34 |
203 |
Total |
104 |
721 |
101 |
926 |
At the 0.05 level of significance, is there evidence of a significant relationship between sales performance level and level of investment in customer satisfaction?
1)
observed frequencey, O | expected proportion | expected frequency,E | (O-E) | (O-E)²/E | |
96 | 0.250 | 65.00 | 31.00 | 14.785 | |
76 | 0.250 | 65.00 | 11.00 | 1.862 | |
50 | 0.250 | 65.00 | -15.00 | 3.462 | |
38 | 0.250 | 65.00 | -27.00 | 11.215 |
chi square test statistic,X² = Σ(O-E)²/E =
31.323
level of significance, α= 0.05
Degree of freedom=k-1= 4 -
1 = 3
P value = 0.0000 [ excel function:
=chisq.dist.rt(test-stat,df) ]
Decision: P value < α, Reject Ho
There is enough evidence of difference
among the age groups in the proportion of smartphone owners who
have reached the maximum amount of data they are allowed to use as
part of their plan, at least on occasion
===============
(Test for independence among proportions)
Ho: There is no significant relationship between sales performance level and level of investment in customer satisfaction
Ha: There is a significant relationship between sales performance level and level of investment in customer satisfaction
Chi-Square Test of independence | |||||||
Observed Frequencies | |||||||
Level Of Investment | Top | Middle | Bottom | Total | |||
Annually | 53 | 318 | 44 | 415 | |||
Every 2-4 years | 40 | 245 | 23 | 308 | |||
Never | 11 | 158 | 34 | 203 | |||
Total | 104 | 721 | 101 | 926 | |||
Expected frequency of a cell = sum of row*sum of column / total sum | |||||||
Expected Frequencies | |||||||
Top | Middle | Bottom | Total | ||||
Annually | 104*415/926=46.609 | 721*415/926=323.126 | 101*415/926=45.265 | 415 | |||
Every 2-4 years | 104*308/926=34.592 | 721*308/926=239.814 | 101*308/926=33.594 | 308 | |||
Never | 104*203/926=22.799 | 721*203/926=158.059 | 101*203/926=22.141 | 203 | |||
Total | 104 | 721 | 101 | 926 | |||
(fo-fe)^2/fe | Top | Middle | Bottom | total | |||
Annually | 0.876 | 0.081 | 0.035 | 0.993 | |||
Every 2-4 years | 0.846 | 0.112 | 3.341 | 4.299 | |||
Never | 6.106 | 0.000 | 6.351 | 12.458 |
Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe =
17.749
Level of Significance = 0.05
Number of Rows = 3
Number of Columns = 3
Degrees of Freedom=(#row - 1)(#column -1) = (3- 1 ) * ( 3- 1 )
= 4
p-Value = 0.001 [Excel function:
=CHISQ.DIST.RT(χ²,df) ]
Decision: p-value < α , Reject
Ho
there is a evidence of a significant relationship between sales performance level and level of investment in customer satisfaction