You are titrating 110.0 mL of 0.050 M Ca2 with 0.050 M EDTA at pH 9.00....

You are titrating 110.0 mL of 0.050 M Ca2 with 0.050 M EDTA at pH 9.00. Log Kf for the Ca2 -EDTA complex is 10.65, and the fraction of free EDTA in the Y4– form, αY4–, is 0.041 at pH 9.00. PLEASE ANSWER ALL PARTS: A, B, C, D, AND E.

(a) What is K\'f, the conditional formation constant, for Ca2 at pH 9.00?

(b) What is the equivalence volume, Ve, in milliliters?

(d) Calculate the concentration of Ca2 at V = Ve.

(e) Calculate the concentration of Ca2 at V = 1.1 Ve.

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Expert Solution

queen_honey_blossom answered 1 year ago

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