Question

In: Statistics and Probability

The high temperatures (in degrees Fahrenheit) of a random sample of 8 small towns are: 97.2...

The high temperatures (in degrees Fahrenheit) of a random sample of 8 small towns are:

97.2
99.9
98
96.3
96.6
96.4
98.5
98.1



Assume high temperatures are normally distributed. Based on this data, find the 98% confidence interval of the mean high temperature of towns. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).

98% C.I. = _____

Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places

Solutions

Expert Solution

please like ??


Related Solutions

The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 99.3 99.1 97.6 97.4 97.9 97.1 97.2 Assume body temperatures of adults are normally distributed. Based on this data, find the 99% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 99% C.I. =    
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 96.8 98.3 99.6 96.7 97.1 97.5 97 99.5 99 99.2 98.4 Assume body temperatures of adults are normally distributed. Based on this data, find the 95% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 95% C.I. =
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98.7 97.9 98.6 99 98.1 98 96.5 99.1 99.6 97 99.3 Assume body temperatures of adults are normally distributed. Based on this data, find the 90% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 90% C.I. =
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98.3 96.7 98.6 98.2 97.7 99.5 99.4 98 Assume body temperatures of adults are normally distributed. Based on this data, find the 80% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 80% C.I. =
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 99.2 98.8 96.4 99.9 96.3 97.4 99.3 98.4 98.1 97.9 98.7 98.5 96.6 Assume body temperatures of adults are normally distributed. Based on this data, find the 95% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 95% C.I....
The following data show the body temperatures (in degrees Fahrenheit) from a random sample of 12...
The following data show the body temperatures (in degrees Fahrenheit) from a random sample of 12 independent healthy people in the United States. 98.5 98.2 99.1 96.6 98.1 98.7 97.5 99.0 97.4 98.3 97.8 98.2 What would be the estimate of the average body temperature of healthy people in the United States. Find a 95% confidence interval for the average body temperature of healthy people in the United States. Explain carefully the interval you found in part (b) means. can...
Daily high temperatures in degrees Fahrenheit in the city of Lubbock for the last week havebeen...
Daily high temperatures in degrees Fahrenheit in the city of Lubbock for the last week havebeen as follows: 93, 94, 93, 95, 96, 88, 90. Using Excel’s Data Analysis add-in, a. Forecast the high temperature today, using a 3-day moving average. b. Forecast the high temperature today, using a 2-day moving average. c. Forecast the high temperature today, using weighted moving average with weights 0.5, 0.3 and 0.2 for the most recent, second most recent, and third most recent periods,...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 84.6 81.1...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 84.6 81.1 95.7 65.5 90.8 80.6 Find the 90% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 90% C.I. =  
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 62.4 102.8...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 62.4 102.8 79.9 52.7 45.5 70.6 76.2 102.3 62.4 Find the 98% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 98% C.I. = Answer should be obtained without any preliminary rounding.
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 78.1 70.7...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 78.1 70.7 73.8 80.1 63.1 66.8 69 78.1 66.4 76.5 70.7 68.5 Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places. Use (lower, upper) formats. 99% C.I. =
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT