Question

a. Chocolate chip cookies have a distribution that is approximately norma with a mean of 23.2 chocolate chips per cookie and a standard deviation of 2.9 chocolate chips per cookie, Find P10 and P90.

b. How might those values be helpful to the producer of the cookies?

Answer 1

P10 : 0.100 = -1.282 (z score)

µ + (x × σ)

= 23.2 + (-1.282*2.9) = 19.482

=19.5 (Rounded to one decimal places)

P90: 0.900 = 1.282 (z score)

µ + (x × σ)

= 23.2 + (1.282*2.9) = 26.918

= 26.9 (Rounded to one decimal places)

How might those values be helpful to the producer of the cookies?

These values shows the percentages of amount of chips in the cookies. Thus, the more the percentage considered, the more the amount of chips in the cookies. This can be used to control the number of chips in cookies during production.