In: Statistics and Probability
Determine whether the conclusion is true or false, and explain why.
1. In a one-way (between-subjects) ANOVA, if the observed group means in the sample differ entirely due to random variations (i.e., sampling errors), the critical value for testing the ratio of between-group mean squares to within-group mean squares will depend on the total sample size (among other aspects).
2. A significant result (i.e., p<.05) from a one-way (between-subjects) ANOVA implies that the means of the groups are all different from one another in the population.
3. A researcher conducted an independent-samples t-test to test his research hypothesis, and obtained a very small p-value which is less than .001. This implies that the probability of type 1 error is less than .1%, assuming no flaws in data collection and analysis.
(1)
Correct option:
True
Explanation:
The Degrees of Freedom for testing the ratio of between-group mean squares to within-group mean squares :
The Degrees of Freedom for numerator = k - 1
where k is the number of groups.
The Degrees of Freedom for denominator = N - k,
where N is the total sample size.
So, we understand that the critical value for testing the ratio of between-group mean squares to within-group mean squares will depend on the total sample size (among other aspects).
(2)
Correct option:
False
Explanation:
A significant result (i.e., p<.05) from a one-way (between-subjects) ANOVA implies that the difference is significant. Reject null hypothesis.
Conclusion:
At least the mean of one group is different from other groups.
(3)
Correct option:
False
Explanation:
Low value of p - value does not imply that = the probability of type 1 error is less than .1%, assuming no flaws in data collection and analysis.