In: Statistics and Probability
From past experience, Dr. R-P believes that the
average score on a Research Methods Course is 75. A sample of 10
students exam scores is as follows:
80, 68, 72, 73, 76, 81, 71, 71, 65, 53.
Test the claim that the students average is still 75. Use α = 0.01.
[You need to first compute the mean and the standard deviation,
then the standard error from your sample. To do this, use the
computational method for ungrouped data that we learned in chapter
5, page 128-129. (Show all your work; this gives you a complete
view of where all these numbers we use in hypothesis testing or
confidence interval come from)].
X | X2 | |
80 | 6400 | |
68 | 4624 | |
72 | 5184 | |
73 | 5329 | |
76 | 5776 | |
81 | 6561 | |
71 | 5041 | |
71 | 5041 | |
65 | 4225 | |
53 | 2809 | |
Sum = | 710 | 50990 |
The sample mean is computed as follows:
Also, the sample variance is
Therefore, the sample standard deviation s is
Null hypothesis: The average score is 75
Alternate hypothesis: The average score is different than 75
At α = 0.01 and df = n - 1 = 10 - 1 = 9 critical t value, t_c = 3.25
t = -1.58
Reject H0 if |t| < t_c
|t| = 1.58 < 3.25 = t_c
H0 is rejected
hence, The average score is different than 75