In: Finance
Please use Microsoft excel to solve the following questions.
1a) You borrowed a 15-year loan of $1,000,000 from a bank. Interest is compounded monthly and the annual interest rate is 2.5%. Find the monthly repayment amount.
1b) You borrowed a 10-year loan of $1,200,000 from a bank. Interest
is compounded monthly and the annual interest rate is 2%. What is
the total interest expense of the loan?
1c) You borrowed $50,000 from a bank 2 years ago at an unknown interest rate. You only know that interest is compounded monthly; and your monthly repayment is $3,000 with a payment holiday in August of each year. Assuming there is no handling fee or any other charges, find the APR of the loan.
1d) You borrowed $50,000 from a bank 2 years ago at an unknown interest rate. You only know that interest is compounded monthly; and your monthly repayment is $3,000 with a payment holiday in August of each year. Assuming there is no handling fee or any other charges, what is the total interest expense of the loan?
1e) You borrowed $388,800 from a bank. Interest is compounded annually and the annual interest rate is 3%. Suppose you make a yearly repayment of $30,000 every year. How many years does it take to pay off the debt? (Round up to the nearest year)
1a) Use the PMT function in excel
Number of periods(12 months in a year)= 15*12=180
Rate of interest per period = 0.025/12=0.00208333
Loan amount | 1000000 |
Rate of interest per year | 0.025 |
Rate of interest per period | 0.002083333 |
Number of years | 15 |
Number of periods | 180 |
PMT | ($6,667.89) |
Hence, the monthly payment amount is $6667.89
1b) Using the CUMIPMT function in excel
Start_period =1
End_period = 120
Start period and end period to calculate the total interest payments between 1st installment and 20th installment.
Loan amount | 1200000 |
Rate of interest per year | 0.02 |
Rate of interest per period | 0.001666667 |
Number of years | 10 |
Number of periods | 120 |
CUMIPMT | ($122,789.09) |
1c)
This question could be solved using excel solver.
Steps:
Create a payment schedule for the past 2 years( skip August payments)
We are calculating future value since we want to know the present value of payments made over the past 2 years
For eg. the future value factor for month 2 is (1+r/12)^(24-2). Here, you must give any cell reference to 'r' (Interest rate cell)
Multiply all the payments with the future value factor ( This is 'Value today' column)
Sum all the 'Value today' column entries ( This is value of the loan today)
Now, go in Data=> Solver=> Set target cell (Value of the loan today) cell => Equal to value of 0 => By changing cell ( Interest rate) => Solve
Hence, we get APR = 28.5896%
Year | Month | Month name | Future value factor | Value today ( after 2 years) | ||||
0 | 0 | 1-Jan | -50000 | 1.75960225 | -87980.11252 | Interest rate | 0.285896449158952 | |
1 | 1 | January | 3000 | 1.718655785 | 5155.967354 | |||
1 | 2 | February | 3000 | 1.678662156 | 5035.986467 | |||
1 | 3 | March | 3000 | 1.63959919 | 4918.79757 | |||
1 | 4 | April | 3000 | 1.601445231 | 4804.335694 | |||
1 | 5 | May | 3000 | 1.564179127 | 4692.53738 | |||
1 | 6 | June | 3000 | 1.527780215 | 4583.340645 | |||
1 | 7 | July | 3000 | 1.492228317 | 4476.684951 | |||
1 | 8 | August | 0 | 1.457503722 | 0 | |||
1 | 9 | September | 3000 | 1.423587179 | 4270.761536 | |||
1 | 10 | October | 3000 | 1.390459883 | 4171.37965 | |||
1 | 11 | November | 3000 | 1.35810347 | 4074.31041 | |||
1 | 12 | December | 3000 | 1.3265 | 3979.5 | |||
2 | 13 | January | 3000 | 1.295631952 | 3886.895857 | |||
2 | 14 | February | 3000 | 1.265482213 | 3796.446639 | |||
2 | 15 | March | 3000 | 1.236034067 | 3708.102201 | |||
2 | 16 | April | 3000 | 1.207271188 | 3621.813565 | |||
2 | 17 | May | 3000 | 1.17917763 | 3537.53289 | |||
2 | 18 | June | 3000 | 1.151737817 | 3455.213452 | |||
2 | 19 | July | 3000 | 1.124936537 | 3374.809612 | |||
2 | 20 | August | 0 | 1.098758931 | 0 | |||
2 | 21 | September | 3000 | 1.073190485 | 3219.571455 | |||
2 | 22 | October | 3000 | 1.048217025 | 3144.651074 | |||
2 | 23 | November | 3000 | 1.023824704 | 3071.474112 | |||
2 | 24 | December | 3000 | 1 | 3000 | |||
Value of the loan today | 4.48858E-08 |
1d) Referring to the above table, enter the start period and end period as in the column. Total cumipmt is the sum of the 3 intervals of cumulative interest.
CUMI PMT | |
From month 1-7 | -6183.56354 |
From month 9-19 | -6701.43722 |
From month 21-24 | -612.768312 |
Total cumipmt | -13497.7691 |
1e.) Using the nper function in excel
PV of Loan | -388800 |
Rate | 0.03 |
PMT | 30000 |
nper | 16.65599 |
PMT is the monthly payment.
PV of loan is taken negative since the sign of inflows and outflows should be different.
Hence, it takes approximately 17 years to pay off the debt