Question

In: Statistics and Probability

A small country consists of ve states, whose populations are A : 810, 000 B :...

A small country consists of ve states, whose populations are A : 810, 000 B : 473, 000 C : 292, 000 D : 594, 000 E : 211, 000 If the legislature has 119 seats, apportion the seats using (a) Hamilton's Method (b) Jeerson's Method (c) Webster's Method (d) Huntington-Hill Method (e) Lowndes' metho

Solutions

Expert Solution

A. Hamilton Method :

Total Seats 119
Divisor 20000
States Population Quota Initial Final
A 810000 40.50 40 40
B 473000 23.65 23 24
C 292000 14.60 14 15
D 594000 29.70 29 30
E 211000 10.55 10 10
Total 2380000 119 116 119

The Divisor is obtained by dividing the total of population by total no of seats, which is 2380000/119.

The Quota is obtained by dividing the population with the divisor. The numbers highlighted in green are added 1 seats in the final quota , which takes the final total to 119.

B. Jefferson's Method :

Total Seats 119
Standard Divisor 20000
Modified Divisor 19700
States Population Quota Initial Final
A 810000 41.12 41 41
B 473000 24.01 24 24
C 292000 14.82 14 14
D 594000 30.15 30 30
E 211000 10.71 10 10
Total 2380000 120.81 119 119

The Quota is obtained by dividing the population with the standard divisor. The sum total was 116. Now , the divisor is reduced until the number of seats , that are apportioned total to 119. Thus , we get the modified divisor as 19700.

C.Webster's Method :

In this case,

Total Seats 119
Standard Divisor 20000
Modified Divisor 20100
States Population Quota Initial Final
A 810000 40.30 40 40
B 473000 23.53 24 24
C 292000 14.53 15 15
D 594000 29.55 30 30
E 211000 10.50 10 10
Total 2380000 118.41 119 119

When we divided the Population by standard divisor, we got the quota, when we rounded it off, we got the sum as 121. Now , we increased the divisor to 20100. Now ,when we round off the allocated quotas, we get the total as 119.

D. Huntington-Hill Method :

Total Seats 119
Standard Divisor 20000
Modified Divisor 20100
States Population Quota Lower Quota Geometric Mean Final
A 810000 40.299 40 40.49691346 40
B 473000 23.532 23 23.49468025 24
C 292000 14.527 14 14.49137675 15
D 594000 29.552 29 29.49576241 30
E 211000 10.498 10 10.48808848 10
Total 2380000 118.41 116 118.4668213 119

Geometric Mean is obtained by the formula , where n is the lower quota.

The highest of the geometric mean and the quota is considered and they are rounded off to get the final. The sum of final is calculated. If it is more than the total seats, then the modified divisor is used and the process is repeated until we get the sum of final apportion as total seats. In this case, the final allocations are shown in the table.


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