Suppose that y has a normal distribution with mean 1 and variance 9. What is the...

Suppose that y has a normal distribution with mean 1 and variance 9. What is the probability that y is in the interval [.7, 2.5]?

Expert Solution

We are given

y has normally distributed with mean = 1 and standard deviation

=3

P[ 0.7 y 2.5 ] = P[( 0.7 - )/ (y- )/ (2.5 - )/ ]

P[ 0.7 y 2.5 ] = P[ (0.7-1)/3 Z (2.5-1)/3]

P[0.7 y 2.5 ] = P( -0.10 Z 0.5)

= P( Z 0.5 ) - P( Z -0.10)

= 0.6915 - 0.4602

P( 0.7 y 2.5) = 0.2313

orchestra answered 1 year ago

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