In: Statistics and Probability
Below is a table of the growth of the Corona Virus in USA and the requests for masks.
| date | corona cases | #of masks req in millions |
| 3/22/2020 | 32 | 2 |
| 3/23/2020 | 42 | 4 |
| 3/24/2020 | 52 | 8 |
| 3/25/2020 | 64 | 12 |
| 3/26/2020 | 81 | 20 |
| 3/27/2020 | 101 | 30 |
| 3/28/2020 | 121 | 40 |
| 3/29/2020 | 140 | 60 |
| 3/30/2020 | 160 | 90 |
| 3/31/2020 | 186 | 110 |
| 4/1/2020 | 212 | 120 |
| 4/2/2020 | 241 | 200 |
| 4/3/2020 | 273 | 300 |
Using causal with masks being the dependent variable. Generate a forecast for the number of masks requested based on the number of Corona cases in the USA. Use a linear regression line. Write the equation as y-hat = a + bx. X is the number of Corona cases and y-hat is the number of masks requested.
What is the value of "a"?
What is the value of "b" ? (Three decimals for both answer.)
a = -62.179
b = 1.058
| r² | 0.881 | |||||
| r | 0.938 | |||||
| Std. Error | 32.102 | |||||
| n | 13 | |||||
| k | 1 | |||||
| Dep. Var. | #of masks req in millions | |||||
| ANOVA table | ||||||
| Source | SS | df | MS | F | p-value | |
| Regression | 83,683.4375 | 1 | 83,683.4375 | 81.21 | 2.07E-06 | |
| Residual | 11,335.6395 | 11 | 1,030.5127 | |||
| Total | 95,019.0769 | 12 | ||||
| Regression output | confidence interval | |||||
| variables | coefficients | std. error | t (df=11) | p-value | 95% lower | 95% upper |
| Intercept | -62.179 | |||||
| corona cases | 1.058 | 0.1174 | 9.011 | 2.07E-06 | 0.7998 | 1.3167 |