Question

Black Friday - the annual shopping tradition the day after Thanksgiving - is often the day which puts retailers "in the black." According to a CNN Money report, consumers spent an average of $378.84 on Black Friday in 2010 with a standard deviation of $247.23. Draw and label a normal curve which would be used to describe the Black Friday expenditures. Based on the values calculated, would it be reasonable to assume the money spent is normally distributed? It is not reasonable to assume the amount of money spent by Black Friday shoppers is normally distributed. It is reasonable to assume the amount of money spent by Black Friday shoppers is normally distributed Completely describe the sampling distribution of the sample mean Black Friday expenditure when samples of size 84 are selected. Mean: μ ¯ y = Standard deviation: σ ¯ y = (round to 4 decimal places) Shape:the distribution of ¯ y is because Using the distribution described in part b, what is the probability of observing a sample mean of $454.633 or more? z = (round to 2 decimal places) probability = (include 4 decimal places) Based on the probability found, what conclusion can be reached? The probability would be classified as . So, there sufficient evidence to conclude the mean amount spent by customers on Black Friday is greater than 378.84.

Answer 1