Question

In: Statistics and Probability

numerical methods ( Chapra & Canale Chapter 17: Linear Regression) Temperature(K) Steam pressure (mmHg) 273 4,6...

numerical methods ( Chapra & Canale Chapter 17: Linear Regression)

Temperature(K)

Steam pressure (mmHg)

273

4,6

303

31,8

323

92,5

343

233,7

363

525,8

The vapor pressure of the water at different temperatures is given in the table below:

a) a. Draw a graph showing the change of vapor pressure with temperature (in Excel file)

b) write how a linear model can be adapted to this data.

c. Fit this data into a linear model.

D. Show actual values and your model on the same chart (in the same Excell file).

to. The difference between the calculated values from the model and the actual values is

Export in the column (in the same Excell file).

Solutions

Expert Solution

a)

b)

Here, the scatterplot shows that pressure and temperature have a linear relationship. Hence, a linear regression model can be applied here.

c)


We will be applying the Linear regression model here, it can be done by using the function LINEST(y_value, x_value, TRUE, TRUE) where y_values contain values of Steam pressure here and x_values have temperature values.

Select 5 rows and 2 columns and then write the formula in the first cell and after that, press Shift + Ctrl + Enter.    

The equation comes out to be -

Steam pressure = -15731.4 + 54.54*Temperature              

d)

Temperature Steam Pressure Predicted Steam pressure
273 46 -841.2459016
303 318 795.0327869
323 925 1885.885246
343 2337 2976.737705
363 5258 4067.590164


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