In: Statistics and Probability
Please use Minitab and follow instructions given with the problem
For each of the following methods, develop a forecast for the number of jobs for the 8th month.
Using the mean squared difference (MSD), explain which of the methods you believe results in the best forecast and make your recommendation to the contractor about what he should expect for the eighth month.
Month |
Jobs |
Feb |
19 |
Mar |
18 |
Apr |
15 |
May |
20 |
Jun |
18 |
Jul |
22 |
Aug |
20 |
Solution : Given that a contractor has recorded the number of jobs performed in the last seven months.
given data is,
month Job
Feb 19
Mar 18
Apr 15
May 20
Jun 18
Jul 22
Aug 20
Here the variable is jobs
a) by the method of moving averages
The minitab commnds are as follows
i) enter the data in minitab
ii) click on stats
ii) click on time series and the dialogue box appers in which we have to select moving averages
iv) keep moving average lengh as 3
v ) under the graph section select
normal plot of residuals and residuals versus fits
The minitab output for moving averages is as follows
Moving Average for Job
Data Job
Length 7
NMissing 0
Moving Average
Length 3
Accuracy Measures
MAPE 8.72054
MAD 1.83333
MSD 6.50000
Here we can see that MSD is 6.5000
From the above plot we can say that the residuals versus fits are not good since the value below and above are
not randomly and equally spread.
The data follows noramality from the above plot.
moving average analysis Plot for Job is as below
b) Using the Exponential smoothing method
The minitab commnds are as follows
i) enter the data in minitab
ii) click on stats
ii) click on time series and the dialogue box appers in which we have to select exponential smoothing
v ) under the graph section select
normal plot of residuals and residuals versus fits
The minitab output for moving averages is as follows
Single Exponential Smoothing for Job
Data Job
Length 7
Smoothing Constant
α 0.229794
Accuracy Measures
MAPE 9.37972
MAD 1.71594
MSD 4.92260
The MSD is 4.92260
The residual versus fits shows that there is randomness and the poits are spread above and below the line eqaully which means that the fit is good
The data follows normality.
exponential smoothing analysis plot for actual versus predicted
is as follows
c) Using the linear trend eqaution :
The minitab commnds are as follows
i) enter the data in minitab
ii) click on stats
ii) click on time series and the dialogue box appers in which we have to select trend analysis
select linear as shown in above box
v ) under the graph section select
normal plot of residuals and residuals versus fits
The minitab output for moving averages is as follows
Trend Analysis for Job
Data Job
Length 7
NMissing 0
Fitted Trend Equation
Yt = 16.86 + 0.500×t
Accuracy Measures
MAPE 8.08588
MAD 1.44898
MSD 3.12245
Here the MSD is 3.2245
The residual versus fits shows that there is randomness and the poits are spread above and below the line eqaully which means that the fit is good
The data follows normality.
Linear trend analysis plot for actual versus predicted is as follows
The trend line fit is good as comapred to exponential smoothing and moving average method
Here the Mean squared deviation (MSD) is always computed using the same denominator, n, regardless of the model. MSD is a more sensitive measure of an unusually large forecast error than MAD.
Notation
Term | Description |
---|---|
yt | actual value at time t |
fitted value | |
n |
number of observations |
Hence from the above analysis we can see that
moving averages | Exponential smoothing | linear trend | |
MSD | 6.5 | 4.9226 | 3.12245 |
Hence we will use the fit which will have minimum MSD and the linear trend gives the minimum MSD
Hence, Using the mean squared difference (MSD), linear trend fit is method we believe results in the best forecast.