Question

In: Statistics and Probability

A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater...

A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 9 phones from the manufacturer had a mean range of 1120 feet with a standard deviation of 38 feet. A sample of 14 similar phones from its competitor had a mean range of 1060 feet with a standard deviation of 37 feet. Do the results support the manufacturer's claim? Let μ1 be the true mean range of the manufacturer's cordless telephone and μ2 be the true mean range of the competitor's cordless telephone. Use a significance level of α=0.01 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 1 of 4 : State the null and alternative hypotheses for the test.

Step 2 of 4:Compute the value of the t test statistic. Round your answer to three decimal places.

  Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H 0   . Round your answer to three decimal places.

Step 4 of 4:State the test's conclusion.

Solutions

Expert Solution

there is sufficient evidence to conclude that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor.


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