In: Statistics and Probability
The time married men with children spend on child care averages 6.0 hours per week (Time, March 12, 2012). You belong to a professional group on family practices that would like to do its own study to determine if the time married men in your area spend on child care per week differs from the reported mean of 6.0 hours per week. A sample of 40 married couples will be used with the data collected showing the hours per week the husband spends on child care. The sample data is contained in the Excel Online file below. Construct a spreadsheet to answer the following questions.
Calculate the value of the test statistic (to 2 decimals).
What is the -value (to 4 decimals)? Do not round intermediate calculations.
3.0 |
5.4 |
10.6 |
2.8 |
7.7 |
5.6 |
11.1 |
4.9 |
11.4 |
1.9 |
10.6 |
2.8 |
2.6 |
7.1 |
1.5 |
0.8 |
4.7 |
1.7 |
11.5 |
2.7 |
5.7 |
5.0 |
8.9 |
1.6 |
10.4 |
10.5 |
7.1 |
4.6 |
9.3 |
6.4 |
0.7 |
5.3 |
9.1 |
3.9 |
9.8 |
9.7 |
5.1 |
7.0 |
6.9 |
6.8 |
Null hypothesis
Alternative hypothesis
We have for given sample,
Population mean for given sample=6
Sample mean=6.105
Sample standard deviation= s=3.31
Sample size =n= 40
Degree of freedom = n-1 =39
t test statistic formula is
= 0.20
P value = 0.8425........................by using Excel command =TDIST(0.2,39,2)
t test statistic = 0.20 P value = 0.8425 |