Question

In: Statistics and Probability

An Ad agency would like to know the results from ads placed based on the dollar...

  1. An Ad agency would like to know the results from ads placed based on the dollar amounts spent of a certain ad. The agency decides to run a pilot study in several small markets. The dollar amounts spent on the ad was 2 thousand, 6 thousand and 13 thousand and the sales were in tens of thousands. The data are in the table below. (Use the numbers in the table, don’t put all the zeros after the values or you will get large numbers). Use Regression for your answers

Ad expenditures

2

6

13

Sales

4

17

25

5

19

27

6

21

29

  1. Test the null hypothesis that the means are all equal. Use an alpha of .05.
  2. Find eta square and interpret.
  3. Find the regression equation.
  4. Test to see if the regression equation is significant. Again use an alpha of .05.
  5. Find R square and interpret.

Solutions

Expert Solution

a)

Ho: µ1=µ2=µ3
H1: not all means are equal

treatment 2 6 13
count, ni = 3 3 3
mean , x̅ i = 5.000 19.00 27.00
std. dev., si = 1.0 2.0 2.0
sample variances, si^2 = 1.000 4.000 4.000
total sum 15 57 81 153 (grand sum)
grand mean , x̅̅ = Σni*x̅i/Σni =   17.00
( x̅ - x̅̅ )² 144.000 4.000 100.000
TOTAL
SS(between)= SSB = Σn( x̅ - x̅̅)² = 432.000 12.000 300.000 744
SS(within ) = SSW = Σ(n-1)s² = 2.000 8.000 8.000 18.0000

no. of treatment , k =   3  
df between = k-1 =    2  
N = Σn =   9  
df within = N-k =   6  
      
mean square between groups , MSB = SSB/k-1 =    744/2=   372.0000
mean square within groups , MSW = SSW/N-k =    18/6=   3.0000
      
F-stat = MSB/MSW =    372/3=   124.00

Decision:   p-value<α , reject null hypothesis    
      
there is enough evidence of significant mean difference among three treatments      

b)

eta square ,effect size = SSbet/SST=   0.9764 (large)

c)

x y (x-x̅)² (y-ȳ)² (x-x̅)(y-ȳ)
2 4 25.0000 169.0000 65.000
2 5 25.0000 144.0000 60.000
2 6 25.0000 121.0000 55.000
6 17 1.0000 0.0000 0.000
6 19 1.0000 4.0000 -2.000
6 21 1.0000 16.0000 -4.000
13 25 36.0000 64.0000 48.000
13 27 36.0000 100.0000 60.000
13 29 36.0000 144.0000 72.000
ΣX ΣY Σ(x-x̅)² Σ(y-ȳ)² Σ(x-x̅)(y-ȳ)
total sum 63.00 153.00 186.00 762.00 354.00
mean 7.00 17.00 SSxx SSyy SSxy

Sample size,   n =   9      
here, x̅ = Σx / n=   7.000          
ȳ = Σy/n =   17.000          
SSxx =    Σ(x-x̅)² =    186.0000      
SSxy=   Σ(x-x̅)(y-ȳ) =   354.0      
              
estimated slope , ß1 = SSxy/SSxx =   354/186=   1.9032      
intercept,ß0 = y̅-ß1* x̄ =   17- (1.9032 )*7=   3.6774      
              
Regression line is, Ŷ=   3.677   + (   1.903   )*x

d)

R² =    (SSxy)²/(SSx.SSy) =    0.8842  
Approximately    88.42%   of variation in observations of variable sales , is explained by variable Ad expenditure  


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