Question

In: Statistics and Probability

Ten randomly selected people took an IQ test A, and next day they took a very...

Ten randomly selected people took an IQ test A, and next day they took a very similar IQ test B. Their scores are shown in the table below.

Person A B C D E F G H I J
Test A 85 104 129 112 88 93 116 79 96 104
Test B 85 104 130 117 88 96 119 78 95 104



Consider (Test A - Test B). Use a 0.01 significance level to test the claim that people do better on the second test than they do on the first. Assume differences are normal. (Note: You may wish to use software.)

(a) The test statistic is (at least 2 digits after the decimal)

(b) The critical value is (at least 3 digits after the decimal)

(c) Is there sufficient evidence to support the claim that people do better on the second test?

A. No
B. Yes


(d) Construct a 99% confidence interval for the mean of the differences. Again, use (Test A - Test B) Use 3 digits after the decimal.

Solutions

Expert Solution

a)

test statistic is =-1.58

b)

critical value is =-2.821

c)

A) NO (since test statistic is not less than critical value)

d)

for 99% CI; and 9 degree of freedom, value of t= 3.250
therefore confidence interval=sample mean -/+ t*std error
margin of errror          =t*std error=             2.055
lower confidence limit                     = -3.055
upper confidence limit                    = 1.055
from above 99% confidence interval for population mean =(-3.055,1.055)

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