Question

Find MIN. Write a C# console app consisting of class MIN with the method CalculateMin() and the driver class. Print the MIN and MIN's location. Don't count numbers outside the range [0, 100].

Answer 1

// C# program to create a class MIN with method CalculateMin that returns the index of the minimum element in the input array

using System;

class MIN {
  
   // method that determines and return the index of the minimum element in the input array, arr, if found else returns -1
   // It only considers the numbers in the range [0, 100]
public static int CalculateMin(double[] arr)
{
int minIdx = -1; // set minIdx to -1 i.e no minimum element
       // loop over the array
for(int i=0;i<arr.Length;i++)
{
           // validate ith number is in valid range
if(arr[i] >= 0 && arr[i] <= 100)
// check that if minIdx is not set or ith element < minIdx element, update minIdx to i
               if(minIdx == -1 || arr[i] < arr[minIdx])
minIdx = i;
}
  
// return the index of the minimum element
       return minIdx;
}
}

class MINDriver
{
static void Main() {
  
       // create an array of numbers
double[] arr = {67, 50, 70.5, 12, -3, 102, 45, 16, 12, 66, 23};
  
       // get the index of the minimum element in the above arr
       int idx = MIN.CalculateMin(arr);
  
       // minimum element exists, display the minimum element and its index
if(idx != -1)
Console.WriteLine("Minimum element is "+arr[idx]+" at index: "+idx);
else // no minimum element exists in the valid range
Console.WriteLine("Array does not contain any valid elements");
}
}

//end of program

Output: