In: Statistics and Probability
200 identical toys are to be sent to 5 families (A, B, C, D, E). If each family must get at least 3 toys and the family “A” cannot have more than 30 toys, how many different ways are there to distribute the toys?
Answer:
Given that:
200 identical toys are to be sent to 5 families (A, B, C, D, E). If each family must get at least 3 toys and the family “A” cannot have more than 30 toys, how many different ways are there to distribute the toys?
This is a case of multinomial theorem. Let the toys given to 5 families be a, b, c, d and e
Also ,
and so on ..
If we are given here that:
Therefore,
Therefore, we have here:
Where each one of them is greater than 1.
Therefore the number of solutions of the above equation is computed using the multinomial formula as:
Now let a > 30 toys that is a get more than 30 toys
Let
Therefore, X >= 1
Putting it in the above equation, we have here:
with each one of them:
Number of solutions of above equation using multinomial theorem:
Therefore the number of different ways to distribute the toys here is computed as: