In: Statistics and Probability
Does prison really deter violent crime? Let x represent percent change in the rate of violent crime and y represent percent change in the rate of imprisonment in the general U.S. population. For 7 recent years, the following data have been obtained.
| x | 5.9 | 5.7 | 4.1 | 5.2 | 6.2 | 6.5 | 11.1 | 
| y | 
 −1.8  | 
 −4.1  | 
 −7.0  | 
 −4.0  | 
3.6 | 
 −0.1  | 
 −4.4  | 
A.given Σx = 44.7, Σy = −17.8,Σx2 = 315.05, Σy2 = 117.38, Σxy = −110.66, and r ≈ 0.065.
Verify the given sums Σx, Σy, Σx2, Σy2, Σxy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.)
| Σx = | |
| Σy = | |
| Σx2 = | |
| Σy2 = | |
| Σxy = | |
| r = | 
Find x, and y. Then find the equation of the least-squares
line  = a + bx. (Round your answers for
x and y to two decimal places. Round your answers for a
and b to three decimal places.)
| x | = | |
| y | = | |
| = | + x | 
Find the value of the coefficient of determination r2. What percentage of the variation in y can be explained by the corresponding variation in x and the least-squares line? What percentage is unexplained? (Round your answer for r2 to three decimal places. Round your answers for the percentages to one decimal place.)
| r2 = | |
| explained | % | 
| unexplained | % | 
Considering the values of r and r2,
does it make sense to use the least-squares line for prediction?
Explain your answer. Select one
The correlation between the variables is so low that it makes sense to use the least-squares line for prediction.
The correlation between the variables is so high that it makes sense to use the least-squares line for prediction.
The correlation between the variables is so high that it does not make sense to use the least-squares line for prediction.
The correlation between the variables is so low that it does not make sense to use the least-squares line for prediction.

| n= | 7.0000 | 
| X̅=ΣX/n | 6.3857 | 
| Y̅=ΣY/n | -2.5429 | 
| sx=(√(Σx2-(Σx)2/n)/(n-1))= | 2.2214 | 
| sy=(√(Σy2-(Σy)2/n)/(n-1))= | 3.4669 | 
| Cov=sxy=(ΣXY-(ΣXΣY)/n)/(n-1)= | 0.5010 | 
| r=Cov/(Sx*Sy)= | 0.065 | 
| slope= β̂1 =r*Sy/Sx= | 0.1015 | 
| intercept= β̂0 ='y̅-β1x̅= | -3.1911 | 
b)
| ΣX = | 44.700 | 
| ΣY= | -17.800 | 
| ΣX2 = | 315.050 | 
| ΣY2 = | 117.380 | 
| ΣXY = | -110.660 | 
| r = | 0.065 | 
c)
| X̅=ΣX/n = | 6.39 | 
| Y̅=ΣY/n = | -2.54 | 
| ŷ = | -3.191+0.102x | 
| coeff of determination r2 = | 0.004 | |
| explained = | 0.4% | |
| unexplained= | 99.6% | |
The correlation between the variables is so low that it does not make sense to use the least-squares line for prediction.