Using a 10x objective, you find that your field of view diameter is 1.8mm. Using the...

Using a 10x objective, you find that your field of view diameter is 1.8mm. Using the equation from procedure 2.3, what is the field of view diameter at the 4x objective?

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Expert Solution

[Note: The question commands to use a particular equation and procedure. But as these information are not given here, only the convenient formula and procedure is being used.]

Field of view (FOV) refers to the maximum area visible under a microscope.
Considering the ocular to be 10X, we are calculating the magnification power under 10X and 4X objectives first.
We know, total magnification = objective * ocular
- High power magnification (with 10X objective) = 10X * 10X = 100X
- Low power magnification (with 4X objective) = 4X * 10X = 40X
As mentioned in the question, high power F.O.V. (field of view) = 1.8 mm
Now, using the formula: high power FOV / low power FOV = low power magnification / high power magnification

=> 1.8 / low power FOV = 40X / 100X

=> low power FOV = (100 * 1.8) / 40

=> low power FOV = 4.5 mm

So, the field of view diameter at the 4X objective is 4.5 mm.

[Note: more area is visible under low power objective lens i.e., with less magnification]

gladiator answered 1 year ago

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