Using a 10x objective, you find that your field of view diameter is 1.8mm. Using the...

Using a 10x objective, you find that your field of view diameter is 1.8mm. Using the equation from procedure 2.3, what is the field of view diameter at the 4x objective?

Expert Solution

[Note: The question commands to use a particular equation and procedure. But as these information are not given here, only the convenient formula and procedure is being used.]

Field of view (FOV) refers to the maximum area visible under a microscope.
Considering the ocular to be 10X, we are calculating the magnification power under 10X and 4X objectives first.
We know, total magnification = objective * ocular
- High power magnification (with 10X objective) = 10X * 10X = 100X
- Low power magnification (with 4X objective) = 4X * 10X = 40X
As mentioned in the question, high power F.O.V. (field of view) = 1.8 mm
Now, using the formula: high power FOV / low power FOV = low power magnification / high power magnification

=> 1.8 / low power FOV = 40X / 100X

=> low power FOV = (100 * 1.8) / 40

=> low power FOV = 4.5 mm

So, the field of view diameter at the 4X objective is 4.5 mm.

[Note: more area is visible under low power objective lens i.e., with less magnification]

gladiator answered 1 year ago

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